pokemon23
i need help on the last question of my day.....involves find the product



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pokemon23
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dw:1329810234736:dw

pokemon23
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Am I correct..?

pokemon23
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Hope I don't get rick roll again..

jerwyn_gayo
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dw:1329810349206:dw

chris
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No pokemon  you can check by plugging in a value for w in both sides of the equation

chris
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=) Rewrite (2w+1)^2  will be easier to see that it's a FOIL problem  (2W+1)(2W+1)

sasogeek
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\[\huge (a+b)^2=a^2+2ab+b^2 \]
do the substitution and work it out :)

pokemon23
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oh.....................

pokemon23
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i will do foil then now thanks...

chris
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Can also use sasogeeks method =)

pokemon23
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I got 4w^2+4w+1

pokemon23
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using foil

pokemon23
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im gonna used saso method next ;D