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Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Well, the derivative of tanx = sec^2x. so.. \[f'(x) = 1 + \sec^2x\]

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0hmmmm how do i knw the derivative of tanx = sec^x?

Directrix
 2 years ago
Best ResponseYou've already chosen the best response.0y' =sec²x  1 http://www.wolframalpha.com/input/?i=derivative+of+y+%3Dx+%2B+tan%28x%29

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Well, you have to like memorise the derivative of it.

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0and the book says tan^2x so i assume sec^2x 1 = tan^2x

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Yes. Its a trig identity.

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0oh i belive mimi just asking for my knowledge

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0dont want someone just doing my homework for me

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0id rather learn then just write down the correct answer :)

Directrix
 2 years ago
Best ResponseYou've already chosen the best response.0You have to know the basic trig identities. Just a few of them and they are related.

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0i am just wondering why my book doesnt tell me this before asking this question

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0oh i know the trig identities but not the derivatives

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0like i know 1sin^2 = cos^2

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0but that didnt teach me the derivative of cos^2

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0thanks i looked at it :)

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0so i need to memorize these too?
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