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ChrisV Group Title

Find the derivative of the trigonometric function. f(x)=-x+tanx

  • 2 years ago
  • 2 years ago

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  1. Mimi_x3 Group Title
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    Well, the derivative of tanx = sec^2x. so.. \[f'(x) = -1 + \sec^2x\]

    • 2 years ago
  2. ChrisV Group Title
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    hmmmm how do i knw the derivative of tanx = sec^x?

    • 2 years ago
  3. Directrix Group Title
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    y' =sec²x - 1 http://www.wolframalpha.com/input/?i=derivative+of+y+%3D-x+%2B+tan%28x%29

    • 2 years ago
  4. Mimi_x3 Group Title
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    Well, you have to like memorise the derivative of it.

    • 2 years ago
  5. ChrisV Group Title
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    and the book says tan^2x so i assume sec^2x -1 = tan^2x

    • 2 years ago
  6. Mimi_x3 Group Title
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    Yes. Its a trig identity.

    • 2 years ago
  7. ChrisV Group Title
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    oh i belive mimi just asking for my knowledge

    • 2 years ago
  8. ChrisV Group Title
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    dont want someone just doing my homework for me

    • 2 years ago
  9. ChrisV Group Title
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    lol

    • 2 years ago
  10. ChrisV Group Title
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    id rather learn then just write down the correct answer :)

    • 2 years ago
  11. Directrix Group Title
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    You have to know the basic trig identities. Just a few of them and they are related.

    • 2 years ago
  12. ChrisV Group Title
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    i am just wondering why my book doesnt tell me this before asking this question

    • 2 years ago
  13. ChrisV Group Title
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    oh i know the trig identities but not the derivatives

    • 2 years ago
  14. ChrisV Group Title
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    like i know 1-sin^2 = cos^2

    • 2 years ago
  15. Directrix Group Title
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    http://www.math.com/tables/derivatives/more/trig.htm

    • 2 years ago
  16. ChrisV Group Title
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    but that didnt teach me the derivative of cos^2

    • 2 years ago
  17. ChrisV Group Title
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    thanks i looked at it :)

    • 2 years ago
  18. ChrisV Group Title
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    so i need to memorize these too?

    • 2 years ago
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