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ChrisV

  • 2 years ago

Find the derivative of the trigonometric function. f(x)=-x+tanx

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  1. Mimi_x3
    • 2 years ago
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    Well, the derivative of tanx = sec^2x. so.. \[f'(x) = -1 + \sec^2x\]

  2. ChrisV
    • 2 years ago
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    hmmmm how do i knw the derivative of tanx = sec^x?

  3. Directrix
    • 2 years ago
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    y' =sec²x - 1 http://www.wolframalpha.com/input/?i=derivative+of+y+%3D-x+%2B+tan%28x%29

  4. Mimi_x3
    • 2 years ago
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    Well, you have to like memorise the derivative of it.

  5. ChrisV
    • 2 years ago
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    and the book says tan^2x so i assume sec^2x -1 = tan^2x

  6. Mimi_x3
    • 2 years ago
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    Yes. Its a trig identity.

  7. ChrisV
    • 2 years ago
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    oh i belive mimi just asking for my knowledge

  8. ChrisV
    • 2 years ago
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    dont want someone just doing my homework for me

  9. ChrisV
    • 2 years ago
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    lol

  10. ChrisV
    • 2 years ago
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    id rather learn then just write down the correct answer :)

  11. Directrix
    • 2 years ago
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    You have to know the basic trig identities. Just a few of them and they are related.

  12. ChrisV
    • 2 years ago
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    i am just wondering why my book doesnt tell me this before asking this question

  13. ChrisV
    • 2 years ago
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    oh i know the trig identities but not the derivatives

  14. ChrisV
    • 2 years ago
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    like i know 1-sin^2 = cos^2

  15. Directrix
    • 2 years ago
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    http://www.math.com/tables/derivatives/more/trig.htm

  16. ChrisV
    • 2 years ago
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    but that didnt teach me the derivative of cos^2

  17. ChrisV
    • 2 years ago
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    thanks i looked at it :)

  18. ChrisV
    • 2 years ago
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    so i need to memorize these too?

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