Find the derivative of the trigonometric function. f(x)=-x+tanx

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Find the derivative of the trigonometric function. f(x)=-x+tanx

Mathematics
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Well, the derivative of tanx = sec^2x. so.. \[f'(x) = -1 + \sec^2x\]
hmmmm how do i knw the derivative of tanx = sec^x?
y' =secĀ²x - 1 http://www.wolframalpha.com/input/?i=derivative+of+y+%3D-x+%2B+tan%28x%29

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Well, you have to like memorise the derivative of it.
and the book says tan^2x so i assume sec^2x -1 = tan^2x
Yes. Its a trig identity.
oh i belive mimi just asking for my knowledge
dont want someone just doing my homework for me
lol
id rather learn then just write down the correct answer :)
You have to know the basic trig identities. Just a few of them and they are related.
i am just wondering why my book doesnt tell me this before asking this question
oh i know the trig identities but not the derivatives
like i know 1-sin^2 = cos^2
http://www.math.com/tables/derivatives/more/trig.htm
but that didnt teach me the derivative of cos^2
thanks i looked at it :)
so i need to memorize these too?

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