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ChrisV

  • 3 years ago

Find the derivative of the trigonometric function. g(t)=quadroot(t)+6csct

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  1. ChrisV
    • 3 years ago
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    \[g(x)=\sqrt[4]{t}-6csct\]

  2. ChrisV
    • 3 years ago
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    t^1/4-6csct

  3. ChrisV
    • 3 years ago
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    1/4t^-3/4 - 6csc(t)cot(t)

  4. ChrisV
    • 3 years ago
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    1/4t^3/4 - 6 csc(t)cot(t) ????

  5. ChrisV
    • 3 years ago
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    \[1/4t ^{2/3} - 6\csc(t)\cot(t)\]

  6. ChrisV
    • 3 years ago
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    oops that supposed to be 3/4 >.<

  7. ChrisV
    • 3 years ago
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    \[1/4t ^{3/4} - 6\csc(t)\cot(t)\]

  8. ChrisV
    • 3 years ago
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    thanks a lot

  9. Mimi_x3
    • 3 years ago
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    wait..

  10. Mimi_x3
    • 3 years ago
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    \[\huge \frac{1}{4} t^{\frac{-3}{4}} \]

  11. ChrisV
    • 3 years ago
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    i think when i drop the t to the bottom i lose the - sign

  12. ChrisV
    • 3 years ago
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    on the exponent

  13. ChrisV
    • 3 years ago
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    1/(4t^3/4) - 6 csc(x)cot(x)

  14. ChrisV
    • 3 years ago
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    maybe thats a better way to write it

  15. Mimi_x3
    • 3 years ago
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    \[\huge t^{\frac{1}{4}} =>\frac{1}{4} t^{\frac{1}{4}-1} =>\frac{1}{4} t^{-\frac{3}{4}} \]

  16. Mimi_x3
    • 3 years ago
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    Yeah, that is a better way of writing it, it looks nicer.

  17. ChrisV
    • 3 years ago
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    thanks a lot mimi

  18. ChrisV
    • 3 years ago
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    you are a life saver :)

  19. Mimi_x3
    • 3 years ago
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    yw (:

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