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anonymous
 4 years ago
Find the derivative of the trigonometric function.
y=2xsinx+x^2cosx
anonymous
 4 years ago
Find the derivative of the trigonometric function. y=2xsinx+x^2cosx

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Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3\[y'=\frac{d}{dx}(2xsinx)+ \frac{d}{dx}x^2cosx \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0product rule for addition?

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3use product rule for each term

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1no  apply product rule to each of the two terms  looks like diyad is doing that now

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3First do \( \frac{d}{dx}(2xsinx) \) & then \( \frac{d}{dx}(x^2cosx) \)

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3do you know how to do derivative of 2xsinx ?

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1d (uv)dx = u* dv/dx + v* du/dx where u and v are function of x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02xsix+x^2cosx=2sinx+3xcosx+2xcosxx^2sinx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i mistyped a bunch at first lol

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3\[\frac{d}{dx} (2xsinx)= 2 \frac{d}{dx}(xsinx) =2[x \frac{d}{dx}sinx+sinx \frac{d}{dx}x]\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my last answer is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0atleast thats what the books says in the back.

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3\[ \frac{d}{dx}(2xsinx)=2[xcosx+sinx]\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y=2xsinx+x^2cosx = 2sinx+2xcosx+2xcosxx^2sinx = 4xcosx +2sinx  x^2sinx = 4xcosx + sinx(2x^2)

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.3oh sorry i thought you were taling about the derivative of 2xsinx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did not know i could use product rule on both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0better to learn than wonder :)

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1yep  whenever you have a product of two functions the rule applies
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