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DiyadiyaBest ResponseYou've already chosen the best response.3
\[y'=\frac{d}{dx}(2xsinx)+ \frac{d}{dx}x^2cosx \]
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
product rule for addition?
 2 years ago

DiyadiyaBest ResponseYou've already chosen the best response.3
use product rule for each term
 2 years ago

cwrw238Best ResponseYou've already chosen the best response.1
no  apply product rule to each of the two terms  looks like diyad is doing that now
 2 years ago

DiyadiyaBest ResponseYou've already chosen the best response.3
First do \( \frac{d}{dx}(2xsinx) \) & then \( \frac{d}{dx}(x^2cosx) \)
 2 years ago

DiyadiyaBest ResponseYou've already chosen the best response.3
do you know how to do derivative of 2xsinx ?
 2 years ago

cwrw238Best ResponseYou've already chosen the best response.1
d (uv)dx = u* dv/dx + v* du/dx where u and v are function of x
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
2xsix+x^2cosx=2sinx+3xcosx+2xcosxx^2sinx
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
i mistyped a bunch at first lol
 2 years ago

DiyadiyaBest ResponseYou've already chosen the best response.3
\[\frac{d}{dx} (2xsinx)= 2 \frac{d}{dx}(xsinx) =2[x \frac{d}{dx}sinx+sinx \frac{d}{dx}x]\]
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
my last answer is correct
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
atleast thats what the books says in the back.
 2 years ago

DiyadiyaBest ResponseYou've already chosen the best response.3
\[ \frac{d}{dx}(2xsinx)=2[xcosx+sinx]\]
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
y=2xsinx+x^2cosx = 2sinx+2xcosx+2xcosxx^2sinx = 4xcosx +2sinx  x^2sinx = 4xcosx + sinx(2x^2)
 2 years ago

DiyadiyaBest ResponseYou've already chosen the best response.3
oh sorry i thought you were taling about the derivative of 2xsinx
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
did not know i could use product rule on both sides
 2 years ago

ChrisVBest ResponseYou've already chosen the best response.0
better to learn than wonder :)
 2 years ago

cwrw238Best ResponseYou've already chosen the best response.1
yep  whenever you have a product of two functions the rule applies
 2 years ago
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