## ChrisV Group Title Find the derivative of the trigonometric function. y=2xsinx+x^2cosx 2 years ago 2 years ago

$y'=\frac{d}{dx}(2xsinx)+ \frac{d}{dx}x^2cosx$

2. cwrw238

use product rule

3. ChrisV

use product rule for each term

5. ChrisV

ah ok

6. cwrw238

no - apply product rule to each of the two terms - looks like diyad is doing that now

First do $$\frac{d}{dx}(2xsinx)$$ & then $$\frac{d}{dx}(x^2cosx)$$

do you know how to do derivative of 2xsinx ?

9. cwrw238

d (uv)dx = u* dv/dx + v* du/dx where u and v are function of x

10. ChrisV

so

11. ChrisV

2xsix+x^2cosx=2sinx+3xcosx+2xcosx-x^2sinx

12. ChrisV

2sinx oops

Nope

14. ChrisV

2xsinx

15. ChrisV

4xcosx+2sinx-x^2sinx

16. ChrisV

4xcosx+sinx(2-x^2)

17. ChrisV

i mistyped a bunch at first lol

$\frac{d}{dx} (2xsinx)= 2 \frac{d}{dx}(xsinx) =2[x \frac{d}{dx}sinx+sinx \frac{d}{dx}x]$

19. ChrisV

20. ChrisV

4xcosx+sinx(2-x^2)

21. ChrisV

atleast thats what the books says in the back.

$\frac{d}{dx}(2xsinx)=2[xcosx+sinx]$

23. ChrisV

y=2xsinx+x^2cosx = 2sinx+2xcosx+2xcosx-x^2sinx = 4xcosx +2sinx - x^2sinx = 4xcosx + sinx(2-x^2)

24. cwrw238

thats correct ChrisV

25. ChrisV

thanks guys

oh sorry i thought you were taling about the derivative of 2xsinx

27. ChrisV

did not know i could use product rule on both sides

28. ChrisV

better to learn than wonder :)

29. cwrw238

yep - whenever you have a product of two functions the rule applies