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abdul_shabeer

A man of weight W is standing on a lift which is moving upward with an acceleration a. The apparent wieght of the man is

  • 2 years ago
  • 2 years ago

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  1. Aadarsh
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    See, I think the new weight would be: W1 = m(g + a) = mg + ma = W + ma = W + (W/g)a Please confirm with other experts also.

    • 2 years ago
  2. abdul_shabeer
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    Yes your answer is right

    • 2 years ago
  3. abdul_shabeer
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    Can you explain it in much more detail?

    • 2 years ago
  4. Aadarsh
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    Thanks Yaar.

    • 2 years ago
  5. abdul_shabeer
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    How you got m(g+a)?

    • 2 years ago
  6. Aadarsh
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    see, when the object is moving upward, always add the acceleration due to gravity and the new acceleration. Multiply the sum by mass of the object. U will get the force acting on it.

    • 2 years ago
  7. abdul_shabeer
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    The force acting on it would be the aapparent wieght of man?

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  8. abdul_shabeer
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    apparent

    • 2 years ago
  9. abdul_shabeer
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    Will it be the apparent weight of man?

    • 2 years ago
  10. Aadarsh
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    I think most probably it should be.

    • 2 years ago
  11. abdul_shabeer
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    Ok, Thanks a lot

    • 2 years ago
  12. Aadarsh
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    U r welcome.

    • 2 years ago
  13. salini
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    yes u have given the right formula but how? here it is when the lift is moving up, the normal force is graeter than the weight of man mg but apparent weight or weight in general of a body is determined by the NORMAL FORCE/NORMAL REACTION hence here N-mg=ma N=mg+ma again i repeat when we say the WEIGHT OF A BODY IS SOMETHING IT IS ACTUALLY THE NORMAL REACTION/FORCE AND NOT mg of the body

    • 2 years ago
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