Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

abdul_shabeer

  • 4 years ago

A beaker contains 40 g of water at 20 degree C. Now 50 g of ice is put into the beaker. The resulting temperature will be

  • This Question is Closed
  1. salini
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this problem is done assuming that all ice melts to mix with water first u need to know specific heat of water=4200J/kgK The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius. heat gained by water=heat lost by ice heat gained by water=ms(T2=T1) s is specific heat heat lost by ice=Q=mL+ms(T2-T2') T2'=o degrees(starting temp of moten water) where l is latent heat of ice(heat req to change it from solid to liquid sate) we have heat req to change the stae of ice+heat req to raise temp of melted water(as final temp is not 0degrees celcius) L=335J/g (latent heat of water) equate both to find T2

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy