A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

A beaker contains 40 g of water at 20 degree C. Now 50 g of ice is put into the beaker. The resulting temperature will be

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this problem is done assuming that all ice melts to mix with water first u need to know specific heat of water=4200J/kgK The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius. heat gained by water=heat lost by ice heat gained by water=ms(T2=T1) s is specific heat heat lost by ice=Q=mL+ms(T2-T2') T2'=o degrees(starting temp of moten water) where l is latent heat of ice(heat req to change it from solid to liquid sate) we have heat req to change the stae of ice+heat req to raise temp of melted water(as final temp is not 0degrees celcius) L=335J/g (latent heat of water) equate both to find T2

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.