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skate2400

  • 2 years ago

What are the possible number of positive, negative, and complex zeros of f(x) = 2x3 + 5x2 + 6x - 4 ? Positive: 2 or 0; Negative: 1; Complex: 2 or 0 Positive: 1; Negative: 2 or 0; Complex 2 or 0 Positive: 2 or 1; Negative: 1; Complex: 2 or 0 Positive: 1; Negative: 2 or 0; Complex: 0

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  1. amistre64
    • 2 years ago
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    f(x) changes sign how many times?

  2. wolfgirl
    • 2 years ago
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    f(x) = 2x^3 - 5x^2 + 6x - 4 There are 3 or 1 possible positive zeros. f(-x) = -2x^3 - 5x^2 - 6x - 4 There are no possible negative zeros. There are possibly 2 complex zeros.

  3. amistre64
    • 2 years ago
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    f(x) = 2x3 + 5x2 + 6x - 4 1 | 0 ther eis only 1 sign change; so there is 1 positive root

  4. amistre64
    • 2 years ago
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    and the only difference between the 1 positive options is a complex or not if there are 2 or 0; that implies complex roots as well

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