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bob_s.

Simplify (2z – 3)^2 a)4z^2 – 9 b)4z^2 – 9z c)4z^2 – 12z – 9 d)4z^2 – 12z + 9

  • 2 years ago
  • 2 years ago

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  1. AccessDenied
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    (2z - 3)^2 = (2z - 3)(2z - 3) do you know how to use FOIL on the binomials?

    • 2 years ago
  2. bob_s.
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    no:/

    • 2 years ago
  3. AccessDenied
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    hmm.. I'll stick with using distributive property twice then (2z - 3)(2z - 3) (2z)(2z - 3) + (-3)(2z - 3) 4z^2 - 6z + (-6z) + 9 4z^2 - 12z + 9 ^ this is sufficient for the answer, im just going to go over FOIL a bit. maybe it will help you out. :) ------------------------------------ FOIL is just another way to multiply them together, and somewhat more convenient to do than distributive twice. "F irst O uter I nner L ast" I'll box the terms I am referring to in each step of it: ([2z] - 3)([2z] - 3) The 2z 's are first, so we multiply these first (2z)(2z) = 4z^2 ([2z] - 3)(2z [- 3]) These are the outer terms. next we multiply these and add it onto the previous expression 4z^2 + 2z(-3) = 4z^2 - 6z (2z [- 3)([2z] - 3) These are the inner terms. we next multiply these and add it to the last again 4z^2 - 6z + (-3)(2z) = 4z^2 - 6z - 6z = 4z^2 - 12z (2z [- 3])(2z [- 3]) These are the 'last' terms. Let's just multiply these together and we'll add it to the last and be finished! 4z^2 - 12z + (-3)(-3) = 4z^2 - 12z + 9

    • 2 years ago
  4. mitosuki
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    (2z - 3)^2 (2z - 3)(2z - 3) FOIL: Multiply the FRONT two (for F in FOIL) 2z * 2z 4z^2 Multiply the OUTER terms (O in FOIL) 2z * (-3) -6z Multiply the INNER terms (I in FOIL) -3 * 2z -6z Multiply LAST terms (L in FOIL) -3 * (-3) 9 Therefore, 4z^2 - 6z - 6z + 9 Combine like terms, 4z^2 - 12z + 9

    • 2 years ago
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