how do i draw the locus of points equidistant from the vertices of a triangle ABC?

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how do i draw the locus of points equidistant from the vertices of a triangle ABC?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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pretty sure that would just be the circumcenter of a triangle -- the intersection of the perpendicular bisectors |dw:1329860627424:dw|
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umm.. okay. lol well, i don't believe there can be any other point thats equal distance from the vertices. the circumcenter would be the only point...

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yea i get what you're sayin AccessDenied,. idk where Luis came from....

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