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go there for some accuarate help

I don't have a library card #. That's not going to help me.

240100447204

try that

lemme know what happens

It worked but I don't see it helping me too much.

ok you shouldve pressed the math section

I did.

ok then you fill out the information on the bottom it shouldve let you type in your qestion

Would this be algebra I or II?

algebra 2

What subtopic?

what are your choices

would it be graphing functions?

yes

I just need to know how to graph them.

girl go the bottom of tha page and get a tutor a live tutor will help you out

I don't like that site.

now thats coool im gonna try that

Yeah that seems complicated :-(

my god girl you are hard to please

Lol I've herd that before :-)

Haha. It does take some work, but that process should at least make it easier.

ya try it

oh shadowfiend was here

Still is.

aaaaahhhhhh

have i metntioned you look wonderful today:)

BrizyBabyâ€”the easiest way to answer these question is usually to graph them, honestly.

I don't know how to graph the equations....that's what I need help with.

Got it! Now we're at the heart of the problem :)

Let's start with A then. We have two equations:
3x + 2y = -15
x - 4y = -20

well i give up nice meeting you thoug Brizzy

I need a easy way to know how to graph them.

You too aminah.love18

I don't get how you did the equations but yeah a negative slope goes down left to right.

yeah. So the points are -7.5 and -1.5?

What did I get wrong?

So you can see here that that line is in quadrants II, III, and IV:
|dw:1329863470553:dw|

-1.5 isn't a point, it's the slope, that's all.

So, it's in the third Quadrant?

Well does it mean what quadrant the slope is in?

It probably means what quadrant the two lines meet in, so let's look at the other line.

If we put the two together:
|dw:1329864317169:dw|

You can see there that they do in fact intersect in quadrant III.

So for A it's Quadrant III?

I would assume so. Again, the question isn't *super* clear, but I think that's what it's asking for.

Okay thanks :-)

Glad I could help :)