What quadrant are the equations in? A. 3x + 2y = -15 x - 4y = -20 B. 10x - y = -30 x - y = -2 C. 2x - 5y = 10 x + 2y = 10 D. 3x + y = 9 -7x - 7y = -14

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What quadrant are the equations in? A. 3x + 2y = -15 x - 4y = -20 B. 10x - y = -30 x - y = -2 C. 2x - 5y = 10 x + 2y = 10 D. 3x + y = 9 -7x - 7y = -14

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http://lhh.tutor.com/presession.aspx?ProgramGUID=c2f98cc5-be2f-42f3-abbd-891c960a6bd5&TopicId=1&InterfaceId=k12&InterfaceType=k12
go there for some accuarate help
I don't have a library card #. That's not going to help me.

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240100447204
try that
lemme know what happens
It worked but I don't see it helping me too much.
ok you shouldve pressed the math section
I did.
ok then you fill out the information on the bottom it shouldve let you type in your qestion
Would this be algebra I or II?
algebra 2
What subtopic?
what are your choices
would it be graphing functions?
yes
I just need to know how to graph them.
girl go the bottom of tha page and get a tutor a live tutor will help you out
I don't like that site.
lol ok then well their helpful i jsut uesd them rite now and they gave me the rite answer to everyting
Brizy, here's something else you can also try. Go to http://fooplot.com. It will graph the equations for you and you can see what quadrants they are in. You do have to solve for y first. So your first equation in A would be: 3x + 2y = -15 2y = -3x - 15 y = (-3/2)x - (15/2) Then you'd enter everything right of the "=" sign on that website. Hope that helps.
now thats coool im gonna try that
Yeah that seems complicated :-(
my god girl you are hard to please
Lol I've herd that before :-)
Haha. It does take some work, but that process should at least make it easier.
ya try it
oh shadowfiend was here
Still is.
aaaaahhhhhh
have i metntioned you look wonderful today:)
BrizyBaby—the easiest way to answer these question is usually to graph them, honestly.
I don't know how to graph the equations....that's what I need help with.
Got it! Now we're at the heart of the problem :)
Let's start with A then. We have two equations: 3x + 2y = -15 x - 4y = -20
well i give up nice meeting you thoug Brizzy
I need a easy way to know how to graph them.
You too aminah.love18
I find it easiest to graph equations when they're in y = mx + b (slope-intercept) form. So first things first, we try to solve the equations for y: \[\begin{align} 3x + 2y &= -15\\ 2y &= -3x - 15\\ y &= \frac{-3x - 15}{2} = -\frac{3}{2}x - \frac{15}{2} \end{align}\] And the other one: \[\begin{align} x - 4y &= -20\\ -4y &= -20 - x\\ y &= \frac{-20 - x}{4} = \frac{-20}{4} - \frac{1}{4}x\\ y &= -5 - \frac{1}{4}x = -\frac{1}{4}x - 5 \end{align}\]
So, we now have: y = -3/2 x - 15/2 y = -1/4x - 5 The first thing to notice is that both of these have a negative slope. Do you know what a negative slope means on a graph?
I don't get how you did the equations but yeah a negative slope goes down left to right.
Whoops. Sorry then, let's go back to that :) Let's start with 3x + 2y = -15. We're trying to solve for y. That means we need y alone. Remember that an equation doesn't change if we subtract the same thing from both sides. So first things first, we move the 3x to the right: 3x + 2y = -15 3x - 3x + 2y = -15 - 3x Subtract 3x from both sides, 3x - 3x is 0: 0 + 2y = -15 - 3x 2y = -15 - 3x (We leave off the 0.) Then we need to get rid of the 2. Dividing the same thing from both sides also leaves the equation unchanged, so we'll divide by 2: y = (-15 - 3x) / 2 y = -15/2 - 3/2 x Does that make more sense?
yeah. So the points are -7.5 and -1.5?
Close! :) This means that the line is, like we said, going top left to bottom right. It means for every 3 units down that it goes, it goes two units to the right. And it means that it meets the y axis at -7.5. A quick, semi-accurate drawing: |dw:1329863330467:dw|
What did I get wrong?
So you can see here that that line is in quadrants II, III, and IV: |dw:1329863470553:dw|
-1.5 isn't a point, it's the slope, that's all.
So, it's in the third Quadrant?
Well, that's what I'm not 100% clear on in the question. Obviously this line goes through three quadrants. Is the question asking which quadrant both lines are in or..?
Well does it mean what quadrant the slope is in?
Sorry -> slope isn't really in a quadrant. It just tells you how the line moves from one position to another (i.e., what angle it's at).
It probably means what quadrant the two lines meet in, so let's look at the other line.
y = -1/4x - 5 So we have a slope of 1/4, meaning for every one unit we go down, we move to the right 4 units. And -5 is the y-intercept, which means the line meets the y axis at -5. Another rough drawing: |dw:1329864223848:dw|
If we put the two together: |dw:1329864317169:dw|
You can see there that they do in fact intersect in quadrant III.
So for A it's Quadrant III?
I would assume so. Again, the question isn't *super* clear, but I think that's what it's asking for.
Okay thanks :-)
Glad I could help :)

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