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logarithmic differentaition
you want dy/dx I assume?

yeah, please

what do you mean two y derivatives?

I can see log x^c = c log x, but I'm confused about the e on the other side of the equation.

\[\ln e=1\]because that's the base of the logarithm

\[\log_aa=1\]in this case we have\[\ln e=\log_ee=1\]

if you don't remember that\[\large \log_aa=1\]you may want to review logarithms

so you agree that \[\log_aa=1\]right?

right

well the natural logarithm is just log base e\[\huge\ln e=\log_ee=1\]

(I just made that big to see the subscripts, sorry if it looks 'loud')

Ha, you bet. Many thanks for walking me through that.

And go Chivas!

lol right on!