A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Kainui
 3 years ago
Best ResponseYou've already chosen the best response.1This is what I did: I took the natural log to both sides xln(xy)=1 I divided x out of each side ln(xy)=1/x Used properties of logarithms to separate out ln(xy) lnx + lny=1/x lny=lnx+1/x then I took the derivative to both sides y'/y=[(1/x^2)+(1/x)] I then multiplied both sides by y, which I just found by using the earlier equation: lny=lnx+1/x y=e^(lnx+1/x) y'=[(1/x^2)+(1/x)][e^(lnx+1/x)] But I'm sure there's an easier or different way, I just went about it this route since this is where I felt most comfortable.

keketsu
 3 years ago
Best ResponseYou've already chosen the best response.2Very interesting. I asked the question somewhere else and got a different approach but same response. This is actually very helpful to see it done a couple different ways. And thanks for the extra explanations!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.