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given - [g = 9.8ms ^{-2} \], \[density of water = 1000 kg m ^{-3}\] and \[1000L = 1 m^{3}\]

(that was a part of the question)

how do you convert the given litres of water to kg?

how did you get that/derive that 1 litre of water has a mas of 1 kg
from the relation given?

He got it from density.
Note that 1000 litres are equal to 1 m^3.

and then? (im not seeing the relation or the beauty here, i'm sorry.)

WAIITTTT

Waiting.

i didnt get a word of that. the thing you wrote under dimensional analysis, i mean. t

if you were gonna explain that, then continue.

i havent learnt about dimensional analysis either.

Therefore, we are left with \[1 \left [ \rm kg \over L \right ]\]

Oh! I see :)

that makes the rest of the problem obvious. thanx! :)

isn't P=W/t? (Power = Work/Time)?

Yes ... eashmore made a small mistake

Whoops! Sorry about that.
I was just testing you. :-P

Looks good. Assuming you typed it into your calculator right.

I calculated it myself lol. I'll double check with a calculator.

Thanks a bunch! :)

Whoops! I got that it should be 22.05 kW.

uhoh! did i make a conversion mistake?

Nope. Everything is good up until you calculate power.
Double check that guy and you should be good.

><

well, maybe i should just listen to the math gods in silence and not be an atheist. :P

I salute you for sticking with me til the end. :D *high five* :P

I salute both of you..
Great work!

LOL! :D