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vengeance921Best ResponseYou've already chosen the best response.1
1=i^2 so complex number cube root would be \[\sqrt[3]{i ^{2}}\] \[(i ^{2})^{1/3}\] \[i ^{2/3}\] \[i ^{2}i ^{3}\] \[1\sqrt{1}\] but the final answer would just be until i^2/3 i think since it is asked in terms of complex numbers
 2 years ago

rivermakerBest ResponseYou've already chosen the best response.0
It may be simpler to do as follows: \[x^3= 1 \rightarrow x^3+1=0 \rightarrow (x+1)(x^2x+1)=0\] This gives x = 1 as the real root and the two complex roots can be obtained by solving the quadratic equation\[x^2x+1\]
 2 years ago
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