Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

aroberts47

  • 2 years ago

PLEASE I need help with two-sided limits

  • This Question is Closed
  1. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What's the question?

  2. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If you want to know what's two-sided limits is, A two sided limit is just the regular limit you see denoted by the lim as x approaches some value of a function. It means that if you approached that value from both sides of the graph you would arrive at the same place. A one sided limit means if you approached the graph from one particular side (from the left or from the right) you would get different values. If the limit from the left does not equal the limit from the right side of the graph, the overall limit does not exist. For example, a function such as y = x, for x > 0 cannot have a negative x-value. So the limit of this function from the left would not exist because the graph doesn't exist there, but the limit from the right would be 0.

  3. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hold on lemme write it out

  4. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1329978579461:dw|

  5. ggrree
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    factor the top and the bottom to get \[x(x+3) \over (x+3)(x-3)\] cancelling gives you: \[x \over x-3\] now you can simply plug in -3.

  6. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Ugh my brain sucks right now good job ggree

  7. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you plug in lim -3^(+) you will get the same answer which means the limit exists

  8. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks.....so what if there was an indeterminate like 40/0 or something, how will I go about solving that?

  9. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  10. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    4/0^(+)= + infinity 4/0^(-) = - infinity If you get 0/0 you did something wrong unless the prof teaches you L'hospitols rule

  11. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    remember you are not using 0 but something infinitly close to zero

  12. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thus 4 or any real number would go into it infinity number of times

  13. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    does that answer your question?

  14. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you had -1/0^(-) = + infinity make sure to note that because a -/- = +

  15. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea it kinda does....thanks

  16. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    are you still confused with something?

  17. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you take the limit from the 0+ of 1/x you get +infinity and if you take the limit from 0- you get -infinity I think I made a mistake with the graph, but yeah the out put as you approach from the right is always increasing and the output from the left is always decreasing

  18. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can I give you another problem to solve?

  19. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sure

  20. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1329979876435:dw|

  21. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but does that explain it but yeah post the question quick need to actually do my own school work lol

  22. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol ok

  23. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    not to rush you

  24. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1329980059353:dw|

  25. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    for these type of questions you multiply by the conjugate so multiply the top and bottom by ((x)^(1/2) + 2)

  26. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    did that help?

  27. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes it did...thanks

  28. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no problem you should be pretty set for limits now if you understand limits going to infinity

  29. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i understand limits going to infinity but i need a resource for some two-sided limit problems. it's kind of confusing/

  30. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    did my 1/x example not help? 1/0- = something like 1/-0.0000001 where as 1/0+ = something like 1/+0.000001 Only these numbers are infinitely small so we end up with lim 1/x = infinity x-> 0+ lim 1/x = -infinity x -> 0- Look at the graph of 1/x |dw:1329981425836:dw| Notice how the output is forever decreasing from the left as you approach zero whereas the output is forever increasing from the right as you approach zero

  31. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thus the limit does not exist

  32. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you took the limit of -1/x you would get the opposite if you took limits at both side so 0+ = -infinity 0- = +infinity

  33. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    as the graph looks like |dw:1329981639188:dw|

  34. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you took the limit of 0+ and 0- of x you would end up with 0 and 0 which means that the limit exists

  35. aroberts47
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh it makes sense to me now

  36. cuddlepony
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok good I was getting tired of explaing it although I should have did it right the first time

  37. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.