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anonymous
 4 years ago
Find the equation of the line that passes through the points (2, 3) and (1, 6).
Write your answer in Standard Form.
Answer
3x – y = 3
3x + y = 3
3x + y = 3
3x – y = 3
anonymous
 4 years ago
Find the equation of the line that passes through the points (2, 3) and (1, 6). Write your answer in Standard Form. Answer 3x – y = 3 3x + y = 3 3x + y = 3 3x – y = 3

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0Standard equation of a line passing through points (x1, y1) and (x2, y2) \[ \frac{yy2}{xx2}=\frac{y2y1}{x2x1}\] here (x1, y1)= (2, 3) and (x2, y2)= (1,6) so we have the equation of line passing through \[ \frac {y(6)}{x1}= \frac{63}{1(2)}\] we get \[ \frac {y+6}{x1}= \frac{9}{3}\] now we have \[ \frac {y+6}{x1}= \frac{3}{1}\] cross multiplying we get \[y+6=3x+3\] so we get \[3x+y=3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the eqn of line is y=mx+c;m=(y2y1)/(x2x1);hence m=(3+6)/(21)=9/3=3. hence y=3x+c; put pt(2,3) as it lies on line and satisfies the eqn hence 3=3*2+c c=36=3; thus eqn of line is 3x+y=3 optn b
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