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You know 1 mole of iridium has a mass of 192.2g. How much should a single atom of iridium weigh?
\[Mass = (\frac{192.2g}{1mol})*(\frac{1mol}{6.022*10^{23}atoms})\]
Below is the figure for a face-centered cubic cell. There are 6 half-atoms and eight 1/8th atoms that make up this cell. How many atoms total is that? (4)
Since you konw what a single atom weights, find out how much the atoms inside the cell weigh, and divide by the volume of the cell (since it's a cube, vol = length^3).
I get about 22.3g/cm^3

Thank you- this was very helpful.

I don't understand how you found the volume, could you please show the math you did?

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