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anonymous
 4 years ago
Write in exponential form. (Will write in equation editor)
anonymous
 4 years ago
Write in exponential form. (Will write in equation editor)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait..that came out funny..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is suppoesd to be a 25 next to log 5

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1\[ 5^{log{5}^{25}}\] ?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\huge 5^{(\log5)^{25}}\]?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1is 5 the base of the logarithm ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Turing Test wrote it correctly.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know how to do it, just am confused about the 5 in the front. what do i do with it?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1the the exponent of the log can come out the front \[5^{log(5)^{25}}=5^{25(log(5)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thats it? I am still confused.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[5^{25\log5}\neq5^{25}\times5^{\log5}\]

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1I have made an error turing test?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\log_5(25)=2\]you are tired

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am reading this off of my math book. 5 is the big dog, while \[\log _{5}25\] is above it.

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1oh yeah i see how wrong that is now

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1well now that we've got it sorted out the problem is trivial goodman please try to post more clearly, that is not what you originally wrote

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1errors ervery where, perhaps i should just watch and learn

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How did you get that? @TuringTest

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\huge 5^{\log_5(25)}=5^2=25\]because\[\huge 5^2=25\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I appologize, srry, i did read it wrong. srry srry.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am new to log, so yea, srry.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1but in general\[\huge a^{\log_a(x)}=x\]so we could have skipped that analaysis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh yea, because it always is equal to the front number. Yea, okay, got it :D Thanx, srry for the mix up :/

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1it's ok, let me know if you have more questions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You are familiar with log? Because dont understand em at all :P

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yes, they can be a bit tricky at first think about small numbers first the definition as I like to give it:\[\huge\log_ax=b\text{ if }a^b=x\]in other words\[\large \log_ax\]asks "what power do we raise a to in order to get x?" for example...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\large\log_2(4)\]asks "2 raised to what power equals 4?" so what is the answer?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1right because 2^2=4 so what about\[\log_2(16)\]?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1right so now you should see why\[\log_5(25)=2\]yes?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0YES!! wow!! It is 5 because 5^5 is equal to 25

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Whoops..srry, so the exponent is the answer?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yeah\[\log_2(16)=4\]as you said, because\[2^4=16\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is that always the case?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1so\[\log_5(25)=2\]because\[5^2=25\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1in general we have\[\huge\log_a(x)=y\iff a^y=x\]so yes, that means always you could say that the question is on the left: "a to what power equals x?" the answer is on the right "a to the y equals x"

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1so do some more what is\[\log_4(16)\]?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1right\[\log_{10}(10000)\] ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think i got it wrong

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1the question is "10 to what power equals 10000" you are asserting that\[\large10^{1000}=10000\]which I dont think you believe what is\[10^2\] ?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[10^{100}\neq10000\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont have a calculator rite now :P

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[10^2=10\cdot10=100\]\[10^3=10\cdot10\cdot10=1000\]the exponent on the ten is the number of zeros after the one so 10 to what power equals 10000 ?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1exactly so\[\log_{10}(10000)=4\]because\[10^4=10000\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That makes its it so simple

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yeah that's a handy rule, and is used in science to describe very large and small numbers last one: how about\[\log_3(81)\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1right :D do you know the basic log rules\[\log(ab)=\log a+\log b\]\[\log(\frac ab)=\log a\log b\]\[\log(a^b)=b\log a\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, we havent been taught those. We started log in class today.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1when you start using that things will be easier \[\large \log(ab)=\log a+\log b\text{ because }x^a\cdot x^b=x^{a+b}\]for example it takes a bit to get used to those ideas though

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yea, just by reading it, I understand the first function.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I also understand the second one, the third one looks funny.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1the third one can be illustrated by the problems we just did first I will ask you what is\[\log_22\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol, i find myself saying "2 raised to what power is 2" thats a neat trick

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1I'm glad, it helps me! and in general\[\log_aa=1\]now look at\[\log_2(16)\]if we factor 16 we get\[\log_2(2^4)\]now apply the third rule\[4\log_2(2)=4(1)=4\]so we get the answer we already knew it also shows that\[\log_aa^x=x\]which is nice to know that's how I did your earlier problem) so by factoring and using these rules we can break down lots of numbers with logs

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1now here's the last grand example\[\log_2(24)=\log_2(2^3\cdot3)\]using the first rule\[\log_2(2^3)+\log_23\]and now the third\[3\log_2(2)+\log_23=3+\log_23\]and that's as far as it goes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wow, i never knew log could be so simple :D

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1I'm glad you feel that way :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanx a ton :D I am now cleared up on log, thank you thank you!!!
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