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Dumb_as_a_Duck

  • 2 years ago

Below is an attachment containing my proof of how the total mechanical energy for a freely falling ball remains constant even at different positions.

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  1. Dumb_as_a_Duck
    • 2 years ago
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  2. Dumb_as_a_Duck
    • 2 years ago
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    There's a problem with page 3, where I've tried to prove that M.E. of the ball at position C when it is on the surface of the ground. My textbook says that at this position, intitial velocity 'u' is zero. I don't find that possible, as just at postion B it was moving with a velocity (when squared) of 2gx. Could you see if my version of deriving is correct? (that's on page 3. the other two have been attached for convenience/reference).

  3. eashmore
    • 2 years ago
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    If the projectile has zero velocity at point C and is resting on the ground, it possess no mechanical energy. This obviously cannot be the case since energy is conserved as the projectile falls. Your proof looks correct.

  4. Dumb_as_a_Duck
    • 2 years ago
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    Thanks. :)

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