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leidyr

  • 4 years ago

Solve p-3√(p) =10

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  1. amitlpu91
    • 4 years ago
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    p-10=3*sqr(p)

  2. amitlpu91
    • 4 years ago
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    now jst squaring both sides

  3. amitlpu91
    • 4 years ago
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    u get quadratic in "p"

  4. Dockworker
    • 4 years ago
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    \[3\sqrt{p}=p-10\] \[3\sqrt{p}=p-10\] squre both sides \[9p=p^2-20p+100\] \[p^2-29p+100=0\] \[(p-25)(p-4)=0\] \[p=25,4\] p=4 4-6=10? false, discard p=4 p=25 25-15=10? true, p=25 is the solution

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