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the slope = 2x
at (2,5) x = 2 so slope of tangent = 2(2) = 4

So your question is to find the slope of the equation\(f(x)=x^2+1\) at (2,5) given f'(x)=2x

joycelefebvre are you new to OS?

OK let me help you

kinda I took calc in college in 93 and its not coming back

OK?

So your given function is \(f(x)=x^2+1\) and \(f'(x)=2x\)

Now as I told you earlier, \(f'(x)\) should be the equation of the tangent at any point

omg I was trying to do y2-y1/x2-x1

Is that clear, any problem?

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Come join me in the chat room (do you know how?)

no

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your 31

See there I have posted you a chat message

Yes, I am 31, thats my level.

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my lap top keeps telling me i cant run this script

OH, I see, what operating system are you using?