Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

joycelefebvre

  • 2 years ago

find slope of tangent line y=f(x)=xsquared + 1 at (2,5) given f'(x)=2x

  • This Question is Closed
  1. cwrw238
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the slope = 2x at (2,5) x = 2 so slope of tangent = 2(2) = 4

  2. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    So your question is to find the slope of the equation\(f(x)=x^2+1\) at (2,5) given f'(x)=2x

  3. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    joycelefebvre are you new to OS?

  4. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes could you show me your work on that please i'm studying for praxis 0061 my study guied doesnt show work its horrible tu

  5. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    OK let me help you

  6. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Given any function, the derivative of the function is the equation to the slope of the given equation--------did you know that?

  7. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    kinda I took calc in college in 93 and its not coming back

  8. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    OK, then I am trying to refresh that. Suppose you have a function y=f(x), so the function y=f'(x) is the equation of the tangent of the function y=f(x)

  9. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    OK?

  10. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    So your given function is \(f(x)=x^2+1\) and \(f'(x)=2x\)

  11. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Now as I told you earlier, \(f'(x)\) should be the equation of the tangent at any point

  12. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Your question asks you to find the equation of the tangent at (2,5) so just put x=2 in the equation to tangent i.e. 2x2=4. So the answer is 4 Got it?

  13. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    omg I was trying to do y2-y1/x2-x1

  14. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    This is actually a theorem.. If you just remember it you don't have to find the tangent that way.......... I mean the way you are trying using the formula \(\frac {y2-y1}{x2-x1}\)

  15. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    The theorem is, Let y=f(x) be a given equation, to find the equation to the tangent at any point is y=f'(x) where f'(x) is the derivative of the function f(x)

  16. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Is that clear, any problem?

  17. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    tu i couldn't find the praxis study guied for 0061 so i got the cliff notes and its all text no examples

  18. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Did you know you can chat with other users in the maths group?

  19. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    In that way you can get help from experts?

  20. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Come join me in the chat room (do you know how?)

  21. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no

  22. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Do you see those green boxes below

  23. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    your 31

  24. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    See there I have posted you a chat message

  25. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes, I am 31, thats my level.

  26. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    But chatting is a different thing

  27. joycelefebvre
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    my lap top keeps telling me i cant run this script

  28. 2bornot2b
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    OH, I see, what operating system are you using?

  29. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.