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cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0the slope = 2x at (2,5) x = 2 so slope of tangent = 2(2) = 4

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2So your question is to find the slope of the equation\(f(x)=x^2+1\) at (2,5) given f'(x)=2x

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2joycelefebvre are you new to OS?

joycelefebvre
 3 years ago
Best ResponseYou've already chosen the best response.0yes could you show me your work on that please i'm studying for praxis 0061 my study guied doesnt show work its horrible tu

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Given any function, the derivative of the function is the equation to the slope of the given equationdid you know that?

joycelefebvre
 3 years ago
Best ResponseYou've already chosen the best response.0kinda I took calc in college in 93 and its not coming back

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2OK, then I am trying to refresh that. Suppose you have a function y=f(x), so the function y=f'(x) is the equation of the tangent of the function y=f(x)

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2So your given function is \(f(x)=x^2+1\) and \(f'(x)=2x\)

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Now as I told you earlier, \(f'(x)\) should be the equation of the tangent at any point

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Your question asks you to find the equation of the tangent at (2,5) so just put x=2 in the equation to tangent i.e. 2x2=4. So the answer is 4 Got it?

joycelefebvre
 3 years ago
Best ResponseYou've already chosen the best response.0omg I was trying to do y2y1/x2x1

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2This is actually a theorem.. If you just remember it you don't have to find the tangent that way.......... I mean the way you are trying using the formula \(\frac {y2y1}{x2x1}\)

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2The theorem is, Let y=f(x) be a given equation, to find the equation to the tangent at any point is y=f'(x) where f'(x) is the derivative of the function f(x)

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Is that clear, any problem?

joycelefebvre
 3 years ago
Best ResponseYou've already chosen the best response.0tu i couldn't find the praxis study guied for 0061 so i got the cliff notes and its all text no examples

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Did you know you can chat with other users in the maths group?

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2In that way you can get help from experts?

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Come join me in the chat room (do you know how?)

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Do you see those green boxes below

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2See there I have posted you a chat message

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2Yes, I am 31, thats my level.

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2But chatting is a different thing

joycelefebvre
 3 years ago
Best ResponseYou've already chosen the best response.0my lap top keeps telling me i cant run this script

2bornot2b
 3 years ago
Best ResponseYou've already chosen the best response.2OH, I see, what operating system are you using?
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