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An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s.
a) If its initial velocity is 6.00 m/s, what is its displacement during the time interval.
b) What is the total distance it travels during the time interval in part b?
 2 years ago
 2 years ago
An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s. a) If its initial velocity is 6.00 m/s, what is its displacement during the time interval. b) What is the total distance it travels during the time interval in part b?
 2 years ago
 2 years ago

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lucifurBest ResponseYou've already chosen the best response.2
specify what part b of the motion is?
 2 years ago

roadjesterBest ResponseYou've already chosen the best response.0
oops, it's supposed to be "What is the total distance it travels during the time interval in part a" not part b. Typo.
 2 years ago

lucifurBest ResponseYou've already chosen the best response.2
27/2 and total distance equals 45/2
 2 years ago

roadjesterBest ResponseYou've already chosen the best response.0
Uh, how do you figure? I mean, what formula did you use? (kinematics)
 2 years ago

lucifurBest ResponseYou've already chosen the best response.2
\[v ^{2}u ^{2} = 2aS\] v=12,u=6 and a=4 u get total displacement S..
 2 years ago

lucifurBest ResponseYou've already chosen the best response.2
for, total distance use the same kinematic equation but twice once till the velocity becomes zero thats from u=6 to v=0; then again from u=0 to v=12
 2 years ago

roadjesterBest ResponseYou've already chosen the best response.0
I'm guessing u=initial velocity and v=final velocity. I get v, but why u?
 2 years ago

roadjesterBest ResponseYou've already chosen the best response.0
And why stop at 0? I mean, I can't visualize the two parts but I think I get the concept.
 2 years ago
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