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## roadjester 3 years ago An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s. a) If its initial velocity is -6.00 m/s, what is its displacement during the time interval. b) What is the total distance it travels during the time interval in part b?

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1. alphyshaju

0

2. lucifur

specify what part b of the motion is?

3. roadjester

oops, it's supposed to be "What is the total distance it travels during the time interval in part a" not part b. Typo.

4. lucifur

27/2 and total distance equals 45/2

5. roadjester

Uh, how do you figure? I mean, what formula did you use? (kinematics)

6. lucifur

\[v ^{2}-u ^{2} = 2aS\] v=12,u=-6 and a=4 u get total displacement S..

7. lucifur

for, total distance use the same kinematic equation but twice once till the velocity becomes zero thats from u=-6 to v=0; then again from u=0 to v=12

8. roadjester

I'm guessing u=initial velocity and v=final velocity. I get v, but why u?

9. roadjester

And why stop at 0? I mean, I can't visualize the two parts but I think I get the concept.

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