What can we afirm about p(x)=x^5 - 5x^3 + 4x^2 - 3x - 2?
a) p(x) has only 3 real roots (1 integer and 2 rationals)
b)p(x) has only one real root, which is also integer
c) x=2 isn't a root of p(x)
d)p(x) has only real roots (1 integer, 2 rationals and 2 irrationals)
So, c is wrong because I divided p(x) by x - 2 and I got x^4 + 2x^3 - x^2 + 2x + 1. Problem is I have no idea how to find the other roots! Help!