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Diyadiya Group Title

Evaluate

  • 2 years ago
  • 2 years ago

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  1. wasiqss Group Title
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    evaluate diya LOl

    • 2 years ago
  2. Diyadiya Group Title
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    Equation editor is not working ?

    • 2 years ago
  3. wasiqss Group Title
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    it is !

    • 2 years ago
  4. Diyadiya Group Title
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    Okay integrate -1 to 3/2 |x sin(pi x)| dx

    • 2 years ago
  5. wasiqss Group Title
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    ok i will

    • 2 years ago
  6. Diyadiya Group Title
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    tell me how to start

    • 2 years ago
  7. Diyadiya Group Title
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    Equation editor is not working :/

    • 2 years ago
  8. wasiqss Group Title
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    ok diya do it by parts i did it

    • 2 years ago
  9. Diyadiya Group Title
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    but there is modulus

    • 2 years ago
  10. wasiqss Group Title
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    ohh dint c the modulus

    • 2 years ago
  11. wasiqss Group Title
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    w8 tellling u

    • 2 years ago
  12. Diyadiya Group Title
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    okay

    • 2 years ago
  13. Diyadiya Group Title
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    http://ncertbooks.prashanthellina.com/class_12.Mathematics.MathematicsPartII/Integral%20ch_7%2006.11.06.pdf Page number 351 (its written on the top right corner)

    • 2 years ago
  14. wasiqss Group Title
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    plz show us how to remove modulus

    • 2 years ago
  15. Diyadiya Group Title
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    full solution is there lol

    • 2 years ago
  16. Diyadiya Group Title
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    i just wanna know that starting part

    • 2 years ago
  17. razor99 Group Title
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    ummm guyzzz

    • 2 years ago
  18. Mertsj Group Title
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    f=x, f'=dx g'=sin pix g=-1/picospix

    • 2 years ago
  19. Diyadiya Group Title
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    Hm What ? sorry can you explain

    • 2 years ago
  20. Mertsj Group Title
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    Do you use u and v or do you use f(x) and g(x) when you integrate by parts.?

    • 2 years ago
  21. Diyadiya Group Title
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    for parts f(x) and g(x)

    • 2 years ago
  22. Mertsj Group Title
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    \[f(x)=x\] \[f'(x)=dx\] \[g'(x)=\sin \pi x\] \[g(x)=-\frac{1}{\pi}\cos \pi \]

    • 2 years ago
  23. wasiqss Group Title
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    bt man how to remove modulus

    • 2 years ago
  24. Diyadiya Group Title
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    Equation editor isn't working

    • 2 years ago
  25. Diyadiya Group Title
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    Can you see the post @wasiqss

    • 2 years ago
  26. Mertsj Group Title
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    I thought you wanted to integrate the function. Didn't know you were trying to remove the modulus.

    • 2 years ago
  27. Diyadiya Group Title
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    Mertsj i cant see what you posted ,it just shows [maths processing error ]

    • 2 years ago
  28. wasiqss Group Title
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    diya i can see tho :P

    • 2 years ago
  29. Diyadiya Group Title
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    Wait let me refresh

    • 2 years ago
  30. wasiqss Group Title
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    mertsj jus remove the modulus first then i will integrate

    • 2 years ago
  31. Mertsj Group Title
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    |dw:1330277056196:dw|

    • 2 years ago
  32. Mertsj Group Title
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    Is that the problem or not?

    • 2 years ago
  33. wasiqss Group Title
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    yes

    • 2 years ago
  34. Mertsj Group Title
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    Then integrate it using the substitutions I gave you.

    • 2 years ago
  35. Diyadiya Group Title
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    |dw:1330277124894:dw|

    • 2 years ago
  36. wasiqss Group Title
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    modulus is thea man

    • 2 years ago
  37. Diyadiya Group Title
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    • 2 years ago
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  38. Mertsj Group Title
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    f(x)=x f'(x)=dx g'(x)=sin pi x g(x)= -1/pi cos pi x

    • 2 years ago
  39. Diyadiya Group Title
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    So we dont have to remove modulus first ?

    • 2 years ago
  40. wasiqss Group Title
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    yeh diya thats my question

    • 2 years ago
  41. Mertsj Group Title
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    Why would you? Integrate the function.

    • 2 years ago
  42. wasiqss Group Title
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    mertsj we have do something with modulus first

    • 2 years ago
  43. Mertsj Group Title
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    Why?

    • 2 years ago
  44. Diyadiya Group Title
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    This is the solution given in my book

    • 2 years ago
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  45. wasiqss Group Title
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    diya this is techniqu for removing modulus that u need to learn from someone cox im not able to recall it

    • 2 years ago
  46. Mertsj Group Title
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    Right. Since it's absolute value there are actually two integrals to do.

    • 2 years ago
  47. Mertsj Group Title
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    Where was the modulus removed in diyadiya's example post?

    • 2 years ago
  48. Mertsj Group Title
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    Which step?

    • 2 years ago
  49. Zarkon Group Title
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    find where x sin(pi x) is positive and negative

    • 2 years ago
  50. wasiqss Group Title
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    as in how

    • 2 years ago
  51. Mr.Math Group Title
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    Which part of the solution don't you understand Diya?

    • 2 years ago
  52. Diyadiya Group Title
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    the beginning

    • 2 years ago
  53. Mr.Math Group Title
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    Alright. You must know that the definition of absolute value, that's |x|=x, if x>=0 and -x if x<0. So we have to find when \(x\sin(\pi x)\) is positive and when it's negative.

    • 2 years ago
  54. Diyadiya Group Title
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    MrMath i cant see Latex

    • 2 years ago
  55. Mr.Math Group Title
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    Lets first consider the interval from (-1,0). x is obviously negative in this interval, and so is sin(pi*x) because sin(pi x) would lie either in the third or fourth quadrant for x in (-1,0). And hence xsin(pi*x) is the product of two negative number which is positve in (-1,0). Following so far?

    • 2 years ago
  56. Mr.Math Group Title
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    Alright. You must know that the definition of absolute value, that's |x|=x, if x>=0 and -x if x<0. So we have to find when xsin(πx) is positive and when it's negative.

    • 2 years ago
  57. Diyadiya Group Title
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    Why is it in the 3rd or 4th Quadrant ?

    • 2 years ago
  58. Mr.Math Group Title
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    Because when x in (-1,0), the angle, πx in (-π,0), right?

    • 2 years ago
  59. Diyadiya Group Title
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    yeah

    • 2 years ago
  60. Mr.Math Group Title
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    So you know why sin(πx) would be negative in this interval?

    • 2 years ago
  61. Diyadiya Group Title
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    okay sine is negetive in 3rd & 4th Quadrant

    • 2 years ago
  62. Mr.Math Group Title
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    And then the xsin(πx) is positve in (-1,0).

    • 2 years ago
  63. Mr.Math Group Title
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    Now in the interval (0,1) is xsin(πx) positive or negative?

    • 2 years ago
  64. Diyadiya Group Title
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    negative ?

    • 2 years ago
  65. Mr.Math Group Title
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    Lets cut it into two pieces. Is x positive or negative in (0,1)?

    • 2 years ago
  66. Diyadiya Group Title
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    wait a minute , i'm trying to understand the previous thing :D 1min

    • 2 years ago
  67. Mr.Math Group Title
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    Take your time :-)

    • 2 years ago
  68. Diyadiya Group Title
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    Alright

    • 2 years ago
  69. Diyadiya Group Title
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    x is positive in (0,1)

    • 2 years ago
  70. Mr.Math Group Title
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    Good. What about sin(πx)?

    • 2 years ago
  71. Diyadiya Group Title
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    Positive

    • 2 years ago
  72. Mr.Math Group Title
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    Great. So xsin(πx) over all is obviously..?

    • 2 years ago
  73. Diyadiya Group Title
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    positive

    • 2 years ago
  74. Mr.Math Group Title
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    What is the next interval we should consider now?

    • 2 years ago
  75. Diyadiya Group Title
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    (1,3/2) ?

    • 2 years ago
  76. Mr.Math Group Title
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    Right, (1,3/2).

    • 2 years ago
  77. Mr.Math Group Title
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    And xsin(πx) will be positive or negative in this interval?

    • 2 years ago
  78. Diyadiya Group Title
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    positive

    • 2 years ago
  79. Mr.Math Group Title
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    Why?

    • 2 years ago
  80. Diyadiya Group Title
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    hm x is positive in (1,3/2)

    • 2 years ago
  81. Diyadiya Group Title
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    its not ?

    • 2 years ago
  82. Mr.Math Group Title
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    Correct. But what about sin(πx)?

    • 2 years ago
  83. Diyadiya Group Title
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    positive ?

    • 2 years ago
  84. Diyadiya Group Title
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    wait

    • 2 years ago
  85. Diyadiya Group Title
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    No its negative

    • 2 years ago
  86. Diyadiya Group Title
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    since the angle is b/w (pi ,3pi/2)

    • 2 years ago
  87. Mr.Math Group Title
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    Very good. That means that xsin(πx) will be negative in (1,3/2), right?

    • 2 years ago
  88. Diyadiya Group Title
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    Yeah

    • 2 years ago
  89. Mr.Math Group Title
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    So now since you know where our expression is positive and negative you can rewrite it using the definition of absolute value. Can you do that?

    • 2 years ago
  90. Mr.Math Group Title
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    We have found that it's positive in (-1,1) and negative in (1,3/2). You agree?

    • 2 years ago
  91. Diyadiya Group Title
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    why (-1,1) ?

    • 2 years ago
  92. Mr.Math Group Title
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    Didn't we just find that it's positive in (-1,0) and in (0,1)?

    • 2 years ago
  93. Diyadiya Group Title
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    Oh yes !!

    • 2 years ago
  94. Mr.Math Group Title
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    Okay, the next step is to write it as it's written in your book. :-)

    • 2 years ago
  95. Diyadiya Group Title
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    Yeah Got it :D

    • 2 years ago
  96. Diyadiya Group Title
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    Thank You soo much :D that was a great explaination :D

    • 2 years ago
  97. Mr.Math Group Title
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    Awesome!

    • 2 years ago
  98. Diyadiya Group Title
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    Now i can do the rest :-) Thanks again :)

    • 2 years ago
  99. Mr.Math Group Title
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    You're welcome!

    • 2 years ago
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