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evaluate diya LOl

Equation editor is not working ?

it is !

Okay integrate -1 to 3/2 |x sin(pi x)| dx

ok i will

tell me how to start

Equation editor is not working :/

ok diya do it by parts i did it

but there is modulus

ohh dint c the modulus

w8 tellling u

okay

plz show us how to remove modulus

full solution is there lol

i just wanna know that starting part

ummm guyzzz

f=x, f'=dx g'=sin pix
g=-1/picospix

Hm What ? sorry can you explain

Do you use u and v or do you use f(x) and g(x) when you integrate by parts.?

for parts f(x) and g(x)

\[f(x)=x\]
\[f'(x)=dx\]
\[g'(x)=\sin \pi x\]
\[g(x)=-\frac{1}{\pi}\cos \pi \]

bt man how to remove modulus

Equation editor isn't working

I thought you wanted to integrate the function. Didn't know you were trying to remove the modulus.

Mertsj i cant see what you posted ,it just shows [maths processing error ]

diya i can see tho :P

Wait let me refresh

mertsj jus remove the modulus first then i will integrate

|dw:1330277056196:dw|

Is that the problem or not?

yes

Then integrate it using the substitutions I gave you.

|dw:1330277124894:dw|

modulus is thea man

f(x)=x
f'(x)=dx
g'(x)=sin pi x
g(x)= -1/pi cos pi x

So we dont have to remove modulus first ?

yeh diya thats my question

Why would you? Integrate the function.

mertsj we have do something with modulus first

Why?

Right. Since it's absolute value there are actually two integrals to do.

Where was the modulus removed in diyadiya's example post?

Which step?

find where x sin(pi x) is positive and negative

as in how

Which part of the solution don't you understand Diya?

the beginning

MrMath i cant see Latex

Why is it in the 3rd or 4th Quadrant ?

Because when x in (-1,0), the angle, πx in (-π,0), right?

yeah

So you know why sin(πx) would be negative in this interval?

okay sine is negetive in 3rd & 4th Quadrant

And then the xsin(πx) is positve in (-1,0).

Now in the interval (0,1) is xsin(πx) positive or negative?

negative ?

Lets cut it into two pieces. Is x positive or negative in (0,1)?

wait a minute , i'm trying to understand the previous thing :D
1min

Take your time :-)

Alright

x is positive in (0,1)

Good. What about sin(πx)?

Positive

Great. So xsin(πx) over all is obviously..?

positive

What is the next interval we should consider now?

(1,3/2) ?

Right, (1,3/2).

And xsin(πx) will be positive or negative in this interval?

positive

Why?

hm x is positive in (1,3/2)

its not ?

Correct. But what about sin(πx)?

positive ?

wait

No its negative

since the angle is b/w (pi ,3pi/2)

Very good. That means that xsin(πx) will be negative in (1,3/2), right?

Yeah

We have found that it's positive in (-1,1) and negative in (1,3/2). You agree?

why (-1,1) ?

Didn't we just find that it's positive in (-1,0) and in (0,1)?

Oh yes !!

Okay, the next step is to write it as it's written in your book. :-)

Yeah Got it :D

Thank You soo much :D that was a great explaination :D

Awesome!

Now i can do the rest :-)
Thanks again :)

You're welcome!