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anonymous
 4 years ago
the electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength of electric field at (x,y)=(2.6,2.8)m?
anonymous
 4 years ago
the electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength of electric field at (x,y)=(2.6,2.8)m?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0E=dV/ds. gradient V= 350(1/2)(x^2+y^2)^(3/2)(2x)+350(1/2)(x^2+y^2)^(3/2)(2y). anything wrong so far?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That kinda how i did it but I keep getting the wrong answer. Let me know if this formula worked for you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my answer's not working either =/

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2wrong so far is that you have written the gradient as a scalar when it is a vector

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2\[\vec E=\nabla V=<350x(x^2+y^2)^{3/2},350y(x^2+y^2)^{3/2}>\]now plug in the variables and find the magnitude of the vector

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2the magnitude is given by\[\large E=\sqrt{E_x^2+E_y^2}\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2welcome, I hope it works

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you cartesian coordiante to spherical coordiante, you will find the answer easier.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0o yea but how? use r=sqrt(x^2+y^2) and then......? can't believe i can't remember how
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