A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x}+1/4\sin(2x)^{2}\]

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.01/2x^1/2 + 1/2sin(2x) * cos(2x) * 2

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0\[1/\sqrt{x} + \sin(2x)\cos(2x)\]

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.1\[{d\over dx} \;\;\; \sqrt x+{1\over4}\sin(2x)^2 = {1\over{2\sqrt x}}+ {2\over2}\sin(2x)\cos(2x)\]

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.1Remember you're also multiplying the \[{1\over \sqrt{x}}\]by \(1\over2\)

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0\[1/\sqrt{x} + 2xcos(2x)^{2}\]

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0is there an identity that makes it 2xcos(2x)^2

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.1Not that I know of. Let me see if I can get wolfram to change it.

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.1Well, when I use wolfram to integrate \({1\over \sqrt{x}}+2x \cos^2 (2x)\) I don't get the original function back, so I'm thinking the book is wrong.

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0k i was wondering myself
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.