Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ChrisV

  • 4 years ago

Find the derivative of the function. sqrt(x) + 1/4(sin(2x)^2)

  • This Question is Closed
  1. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\sqrt{x}+1/4\sin(2x)^{2}\]

  2. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1/2x^-1/2 + 1/2sin(2x) * cos(2x) * 2

  3. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[1/\sqrt{x} + \sin(2x)\cos(2x)\]

  4. KingGeorge
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[{d\over dx} \;\;\; \sqrt x+{1\over4}\sin(2x)^2 = {1\over{2\sqrt x}}+ {2\over2}\sin(2x)\cos(2x)\]

  5. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well the book says

  6. KingGeorge
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Remember you're also multiplying the \[{1\over \sqrt{x}}\]by \(1\over2\)

  7. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[1/\sqrt{x} + 2xcos(2x)^{2}\]

  8. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i mean yes the 1/2

  9. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is there an identity that makes it 2xcos(2x)^2

  10. KingGeorge
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Not that I know of. Let me see if I can get wolfram to change it.

  11. KingGeorge
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Well, when I use wolfram to integrate \({1\over \sqrt{x}}+2x \cos^2 (2x)\) I don't get the original function back, so I'm thinking the book is wrong.

  12. ChrisV
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k i was wondering myself

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy