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bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.3du is tan^2(x) dx.. the rest is for myin.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2\[\int\limits_{}^{}\tan(x) \cdot \tan(x) \sec(x) dx=\tan(x) \cdot \sec(x)\int\limits_{}^{}\sec^2(x) \cdot \sec(x) dx\]

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.3oh wait lol i got it the other way around hahaha

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2And you can look at the integral sec^3(x) and use integration by parts there

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2oh wait i didn't need to do what i did

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2\[\int\limits_{}^{}(\sec^2(x)1)\sec(x) dx=\int\limits_{}^{}\sec^3(x) dx\int\limits_{}^{}\sec(x) dx\]

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.0that person is leaving, just so you know they told me on another post

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2\[\int\limits_{}^{}\sec^3(x) dx=\int\limits_{}^{}\sec^2(x) \sec(x)dx=\tan(x) \sec(x)\int\limits_{}^{}\tan(x) \sec(x) \tan(x) dx\] \[\tan(x) \sec(x)\int\limits_{}^{}(\sec^2(x)1) \sec(x) dx\]

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.0I was doing problems with them for quite a while, but don't worry pretty sure they got what you were saying

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2yay i think there is enough info here

ggrree
 2 years ago
Best ResponseYou've already chosen the best response.0thanks to all of you! I got it now.
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