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dejongrittman

  • 3 years ago

A man walks along a straight path at a speed of 4ft/s. A searchlight is located on the ground 20ft from the path and is kept focused on the man. At what rate is the searchlight rotating when the man is 15 ft from the point on the path closest to the searchlight.

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  1. krypton
    • 3 years ago
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    Now note that tan(y) = x=20, so that sec^2y *dy/dt=1/20 dx/dt At the instant described in the problem, x = 15 and the hypotenuse of the above triangle thus has length 25, so we compute: (25/20)^2 dy/dt=1/20*4 ==>dy/dt=1/2*400/625 =16/125 rad/sec

  2. krypton
    • 3 years ago
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    |dw:1330480851143:dw|

  3. krypton
    • 3 years ago
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    hope this helps

  4. dejongrittman
    • 3 years ago
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    Thank you so mcuh! :)

  5. krypton
    • 3 years ago
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    anytime :)

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