At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

I'd help you if I could, but when you solve this I posted one for you to help me with.

\[y=y_h+y_p\]
\[y_h=c_1 e^{2x}+c_2 e^{-2x}\]
its that yp thats making me loose my religion :)

Wooooooow. Just wondering, where did you get this problem from?

Where the hell did c come into play?

i call it #14 form section 4.3 ... from HELL!!! lol

@Calculus102 It's differential equations. It's like a class after Calc III

Calc 3??? Like multivariate calculus?

I'm done here, I am zero help.

I'm in PRE calculus. This is madness.

\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]

calciii is cake compared to having to deal with this tripe ....

Bernoulli's method, anyone?

this is very simple ,chain rule,product rule and some pellet mixed together

burnoodle aint gonna help on this one

wait nevermind... bernoulli was if u had y^n lol not nth derivative.. i suck at math

I took diff eq's.. use the char equation?
r^2-4r = 0
r(r-4)=0
r = 0, r = 4

but what about the right? i forgot.. and i only took this like a year ago.

yeah the homogenous parts a breeze done did that

the right is one of those "make a good guess" type deals

heres my guess
\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]

ohh one of the rules? anyway i gotta eat dinner, mom's yelling at me lol.

LOL...THIS CAN BE pelletY

satellite, where does your math knowledge come from?

Wait LOOOLL, u're amistre!!! Doesn't matter man, where does your knowledge come from amistre?

You guys are epic! Like seriously! I'm very impressed, look up to you guys :))!

well, I know a = -1/8 regardless of what that other stuff does :)

and b=-f ...

(-8f) x^2+(-8g+8a)x+(-8h+8b+2f)=0x^2+0x+0
f = 0 so b = 0

which means h=0 too for that constant

(-8(0)) x^2+(-8g+8a)x+(-8(0)+8(0)+2(0))=0x^2+0x+0
-8g+8a = 0; and a = -1/8
-8g-1 = 0 ; g = -1/8

2(-1/8)-8c-4(-1/8)=-3
-1/4 -8c +1/2=-3
-8c =-3' 1/4
c =13/32

and i believe the wolf agrees .... yay!!

if JamesJ had been here he could of answered it with one hand tied behind his back ;)

Amistre64? is that you?

remember me its gopeder :)

thats what it says on my nametag :)

Do you Remember me im the bear guy :)

i vaguely recall a screenname like yours; at my age its all i can do to remember to wear socks

xD we talked alot maybe 4 mounts ago

yeah, 4 months is an eternity around here lol how you been?

haha so true :) Not much Just starting Geometry.. its loads of fun

xD oh i will :P

But at the end of the day its really cool because it relates to real world

Refer to the attachment.

We got "derive" at the college that looks quite similar to that kind of thing.