A community for students.
Here's the question you clicked on:
 0 viewing
amistre64
 4 years ago
\[y''4y=(x^23)sin(2x)\]
solve the diffyQ; oy what a nightmare ...
amistre64
 4 years ago
\[y''4y=(x^23)sin(2x)\] solve the diffyQ; oy what a nightmare ...

This Question is Closed

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.3I'd help you if I could, but when you solve this I posted one for you to help me with.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[y=y_h+y_p\] \[y_h=c_1 e^{2x}+c_2 e^{2x}\] its that yp thats making me loose my religion :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wooooooow. Just wondering, where did you get this problem from?

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.3Where the hell did c come into play?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i call it #14 form section 4.3 ... from HELL!!! lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Calculus102 It's differential equations. It's like a class after Calc III

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Calc 3??? Like multivariate calculus?

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.3I'm done here, I am zero help.

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.3I'm in PRE calculus. This is madness.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1calciii is cake compared to having to deal with this tripe ....

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1Bernoulli's method, anyone?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is very simple ,chain rule,product rule and some pellet mixed together

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1burnoodle aint gonna help on this one

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1wait nevermind... bernoulli was if u had y^n lol not nth derivative.. i suck at math

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1its keeping track of the mindnumbingness till the end ... i dont think i have a happy personality left in me after this lol

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1I took diff eq's.. use the char equation? r^24r = 0 r(r4)=0 r = 0, r = 4

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1but what about the right? i forgot.. and i only took this like a year ago.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1yeah the homogenous parts a breeze done did that

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the right is one of those "make a good guess" type deals

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1heres my guess \[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1ohh one of the rules? anyway i gotta eat dinner, mom's yelling at me lol.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\] \[y' _p=(2ax+b)sin(2x)+(2ax^2+2bx+2c)cos(2x)\]\[\hspace{5em} +(2fx+g)cos(2x)+(2fx^22gx2h)sin(2x)\] \[y'' _p=(2a)sin(2x)+(4ax+2b)cos(2x)\]\[\hspace{3em}+(4ax+2b)cos(2x)+(4ax^24bx4c)sin(2x)\]\[\hspace{6em} +(2f)cos(2x)+(4fx2g)sin(2x)\]\[\hspace{9em}+(4fx2g)sin(2x)+(4fx^24gx4h)cos(2x)\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[(4ax^24bx4c)sin(2x)\]\[(2a4ax^24bx4c4fx2g4fx2g)sin(2x)\] \[(4fx^24gx4h)cos(2x)\]\[(4ax+2b+4qx+2b+2f4fx^24gx4h)cos(2x)\] \[(8ax^28bx8c+2a8fx4)sin(2x)=(x^23)sin(2x)\]\[a=\frac{1}{8}\] \[(8bx8c\frac{1}{4}8fx4)=(3)\] ugh ... messed it up again \[(8fx^28gx8h+4b+8ax+4b+2f)cos(2x)=0cos(2x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0LOL...THIS CAN BE pelletY

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1satellite, where does your math knowledge come from?

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1Wait LOOOLL, u're amistre!!! Doesn't matter man, where does your knowledge come from amistre?

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1You guys are epic! Like seriously! I'm very impressed, look up to you guys :))!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[(8ax^28bx8c+2a8fx4g)=(x^23)\] \[(8a)x^2+(8b8f)x+(2a8c4g)=x^2+0x3\] i gots no math knowledge ;)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1well, I know a = 1/8 regardless of what that other stuff does :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i spose we gotta undo the cosines now and have some systems of equations to play with for the remaing terms

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1(8f) x^2+(8g+8a)x+(8h+8b+2f)=0x^2+0x+0 f = 0 so b = 0

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1which means h=0 too for that constant

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1(8(0)) x^2+(8g+8a)x+(8(0)+8(0)+2(0))=0x^2+0x+0 8g+8a = 0; and a = 1/8 8g1 = 0 ; g = 1/8

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.12(1/8)8c4(1/8)=3 1/4 8c +1/2=3 8c =3' 1/4 c =13/32

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[y''4y=(x^23)sin(2x)\] \[y=c_1e^{2x}+c_2e^{2x}(\frac{1}{8}x^2\frac{13}{32})sin(2x)\frac{1}{8}xcos(2x)\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1and i believe the wolf agrees .... yay!!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1if JamesJ had been here he could of answered it with one hand tied behind his back ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Amistre64? is that you?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0remember me its gopeder :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1thats what it says on my nametag :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you Remember me im the bear guy :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i vaguely recall a screenname like yours; at my age its all i can do to remember to wear socks

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0xD we talked alot maybe 4 mounts ago

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1yeah, 4 months is an eternity around here lol how you been?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha so true :) Not much Just starting Geometry.. its loads of fun

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1if you ever meet euclid, punch him in the breadbasket for me. hes to blame for alot of that geometry stuff

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But at the end of the day its really cool because it relates to real world

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1Amistre, sorry to bother you guys, but can you take a look at this? please? http://openstudy.com/study#/updates/4f4d9f77e4b019d0ebade348

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Refer to the attachment.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1We got "derive" at the college that looks quite similar to that kind of thing.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.