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amistre64
Group Title
\[y''4y=(x^23)sin(2x)\]
solve the diffyQ; oy what a nightmare ...
 2 years ago
 2 years ago
amistre64 Group Title
\[y''4y=(x^23)sin(2x)\] solve the diffyQ; oy what a nightmare ...
 2 years ago
 2 years ago

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Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.3
I'd help you if I could, but when you solve this I posted one for you to help me with.
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[y=y_h+y_p\] \[y_h=c_1 e^{2x}+c_2 e^{2x}\] its that yp thats making me loose my religion :)
 2 years ago

Calculus102 Group TitleBest ResponseYou've already chosen the best response.0
Wooooooow. Just wondering, where did you get this problem from?
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.3
Where the hell did c come into play?
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i call it #14 form section 4.3 ... from HELL!!! lol
 2 years ago

Hermeezey Group TitleBest ResponseYou've already chosen the best response.0
@Calculus102 It's differential equations. It's like a class after Calc III
 2 years ago

Calculus102 Group TitleBest ResponseYou've already chosen the best response.0
Calc 3??? Like multivariate calculus?
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.3
I'm done here, I am zero help.
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.3
I'm in PRE calculus. This is madness.
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
calciii is cake compared to having to deal with this tripe ....
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Bernoulli's method, anyone?
 2 years ago

krypton Group TitleBest ResponseYou've already chosen the best response.0
this is very simple ,chain rule,product rule and some pellet mixed together
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
burnoodle aint gonna help on this one
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
wait nevermind... bernoulli was if u had y^n lol not nth derivative.. i suck at math
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
its keeping track of the mindnumbingness till the end ... i dont think i have a happy personality left in me after this lol
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
I took diff eq's.. use the char equation? r^24r = 0 r(r4)=0 r = 0, r = 4
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
but what about the right? i forgot.. and i only took this like a year ago.
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
yeah the homogenous parts a breeze done did that
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the right is one of those "make a good guess" type deals
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
heres my guess \[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
ohh one of the rules? anyway i gotta eat dinner, mom's yelling at me lol.
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\] \[y' _p=(2ax+b)sin(2x)+(2ax^2+2bx+2c)cos(2x)\]\[\hspace{5em} +(2fx+g)cos(2x)+(2fx^22gx2h)sin(2x)\] \[y'' _p=(2a)sin(2x)+(4ax+2b)cos(2x)\]\[\hspace{3em}+(4ax+2b)cos(2x)+(4ax^24bx4c)sin(2x)\]\[\hspace{6em} +(2f)cos(2x)+(4fx2g)sin(2x)\]\[\hspace{9em}+(4fx2g)sin(2x)+(4fx^24gx4h)cos(2x)\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[(4ax^24bx4c)sin(2x)\]\[(2a4ax^24bx4c4fx2g4fx2g)sin(2x)\] \[(4fx^24gx4h)cos(2x)\]\[(4ax+2b+4qx+2b+2f4fx^24gx4h)cos(2x)\] \[(8ax^28bx8c+2a8fx4)sin(2x)=(x^23)sin(2x)\]\[a=\frac{1}{8}\] \[(8bx8c\frac{1}{4}8fx4)=(3)\] ugh ... messed it up again \[(8fx^28gx8h+4b+8ax+4b+2f)cos(2x)=0cos(2x)\]
 2 years ago

krypton Group TitleBest ResponseYou've already chosen the best response.0
LOL...THIS CAN BE pelletY
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
satellite, where does your math knowledge come from?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Wait LOOOLL, u're amistre!!! Doesn't matter man, where does your knowledge come from amistre?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
You guys are epic! Like seriously! I'm very impressed, look up to you guys :))!
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[(8ax^28bx8c+2a8fx4g)=(x^23)\] \[(8a)x^2+(8b8f)x+(2a8c4g)=x^2+0x3\] i gots no math knowledge ;)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
well, I know a = 1/8 regardless of what that other stuff does :)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
and b=f ...
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i spose we gotta undo the cosines now and have some systems of equations to play with for the remaing terms
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
(8f) x^2+(8g+8a)x+(8h+8b+2f)=0x^2+0x+0 f = 0 so b = 0
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
which means h=0 too for that constant
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
(8(0)) x^2+(8g+8a)x+(8(0)+8(0)+2(0))=0x^2+0x+0 8g+8a = 0; and a = 1/8 8g1 = 0 ; g = 1/8
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
2(1/8)8c4(1/8)=3 1/4 8c +1/2=3 8c =3' 1/4 c =13/32
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[y''4y=(x^23)sin(2x)\] \[y=c_1e^{2x}+c_2e^{2x}(\frac{1}{8}x^2\frac{13}{32})sin(2x)\frac{1}{8}xcos(2x)\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
and i believe the wolf agrees .... yay!!
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if JamesJ had been here he could of answered it with one hand tied behind his back ;)
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
Amistre64? is that you?
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
remember me its gopeder :)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
thats what it says on my nametag :)
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
Do you Remember me im the bear guy :)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i vaguely recall a screenname like yours; at my age its all i can do to remember to wear socks
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
xD we talked alot maybe 4 mounts ago
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
yeah, 4 months is an eternity around here lol how you been?
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
haha so true :) Not much Just starting Geometry.. its loads of fun
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if you ever meet euclid, punch him in the breadbasket for me. hes to blame for alot of that geometry stuff
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
xD oh i will :P
 2 years ago

gopeder Group TitleBest ResponseYou've already chosen the best response.0
But at the end of the day its really cool because it relates to real world
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.1
Amistre, sorry to bother you guys, but can you take a look at this? please? http://openstudy.com/study#/updates/4f4d9f77e4b019d0ebade348
 2 years ago

robtobey Group TitleBest ResponseYou've already chosen the best response.0
Refer to the attachment.
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
We got "derive" at the college that looks quite similar to that kind of thing.
 2 years ago
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