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amistre64
 3 years ago
\[y''4y=(x^23)sin(2x)\]
solve the diffyQ; oy what a nightmare ...
amistre64
 3 years ago
\[y''4y=(x^23)sin(2x)\] solve the diffyQ; oy what a nightmare ...

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Lukecrayonz
 3 years ago
Best ResponseYou've already chosen the best response.3I'd help you if I could, but when you solve this I posted one for you to help me with.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[y=y_h+y_p\] \[y_h=c_1 e^{2x}+c_2 e^{2x}\] its that yp thats making me loose my religion :)

Calculus102
 3 years ago
Best ResponseYou've already chosen the best response.0Wooooooow. Just wondering, where did you get this problem from?

Lukecrayonz
 3 years ago
Best ResponseYou've already chosen the best response.3Where the hell did c come into play?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i call it #14 form section 4.3 ... from HELL!!! lol

Hermeezey
 3 years ago
Best ResponseYou've already chosen the best response.0@Calculus102 It's differential equations. It's like a class after Calc III

Calculus102
 3 years ago
Best ResponseYou've already chosen the best response.0Calc 3??? Like multivariate calculus?

Lukecrayonz
 3 years ago
Best ResponseYou've already chosen the best response.3I'm done here, I am zero help.

Lukecrayonz
 3 years ago
Best ResponseYou've already chosen the best response.3I'm in PRE calculus. This is madness.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1calciii is cake compared to having to deal with this tripe ....

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1Bernoulli's method, anyone?

krypton
 3 years ago
Best ResponseYou've already chosen the best response.0this is very simple ,chain rule,product rule and some pellet mixed together

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1burnoodle aint gonna help on this one

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1wait nevermind... bernoulli was if u had y^n lol not nth derivative.. i suck at math

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1its keeping track of the mindnumbingness till the end ... i dont think i have a happy personality left in me after this lol

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1I took diff eq's.. use the char equation? r^24r = 0 r(r4)=0 r = 0, r = 4

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1but what about the right? i forgot.. and i only took this like a year ago.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1yeah the homogenous parts a breeze done did that

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1the right is one of those "make a good guess" type deals

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1heres my guess \[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\]

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1ohh one of the rules? anyway i gotta eat dinner, mom's yelling at me lol.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[y_p=(ax^2+bx+c)sin(2x)+(fx^2+gx+h)cos(2x)\] \[y' _p=(2ax+b)sin(2x)+(2ax^2+2bx+2c)cos(2x)\]\[\hspace{5em} +(2fx+g)cos(2x)+(2fx^22gx2h)sin(2x)\] \[y'' _p=(2a)sin(2x)+(4ax+2b)cos(2x)\]\[\hspace{3em}+(4ax+2b)cos(2x)+(4ax^24bx4c)sin(2x)\]\[\hspace{6em} +(2f)cos(2x)+(4fx2g)sin(2x)\]\[\hspace{9em}+(4fx2g)sin(2x)+(4fx^24gx4h)cos(2x)\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[(4ax^24bx4c)sin(2x)\]\[(2a4ax^24bx4c4fx2g4fx2g)sin(2x)\] \[(4fx^24gx4h)cos(2x)\]\[(4ax+2b+4qx+2b+2f4fx^24gx4h)cos(2x)\] \[(8ax^28bx8c+2a8fx4)sin(2x)=(x^23)sin(2x)\]\[a=\frac{1}{8}\] \[(8bx8c\frac{1}{4}8fx4)=(3)\] ugh ... messed it up again \[(8fx^28gx8h+4b+8ax+4b+2f)cos(2x)=0cos(2x)\]

krypton
 3 years ago
Best ResponseYou've already chosen the best response.0LOL...THIS CAN BE pelletY

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1satellite, where does your math knowledge come from?

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1Wait LOOOLL, u're amistre!!! Doesn't matter man, where does your knowledge come from amistre?

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1You guys are epic! Like seriously! I'm very impressed, look up to you guys :))!

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[(8ax^28bx8c+2a8fx4g)=(x^23)\] \[(8a)x^2+(8b8f)x+(2a8c4g)=x^2+0x3\] i gots no math knowledge ;)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1well, I know a = 1/8 regardless of what that other stuff does :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i spose we gotta undo the cosines now and have some systems of equations to play with for the remaing terms

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1(8f) x^2+(8g+8a)x+(8h+8b+2f)=0x^2+0x+0 f = 0 so b = 0

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1which means h=0 too for that constant

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1(8(0)) x^2+(8g+8a)x+(8(0)+8(0)+2(0))=0x^2+0x+0 8g+8a = 0; and a = 1/8 8g1 = 0 ; g = 1/8

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.12(1/8)8c4(1/8)=3 1/4 8c +1/2=3 8c =3' 1/4 c =13/32

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[y''4y=(x^23)sin(2x)\] \[y=c_1e^{2x}+c_2e^{2x}(\frac{1}{8}x^2\frac{13}{32})sin(2x)\frac{1}{8}xcos(2x)\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1and i believe the wolf agrees .... yay!!

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1if JamesJ had been here he could of answered it with one hand tied behind his back ;)

gopeder
 3 years ago
Best ResponseYou've already chosen the best response.0Amistre64? is that you?

gopeder
 3 years ago
Best ResponseYou've already chosen the best response.0remember me its gopeder :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1thats what it says on my nametag :)

gopeder
 3 years ago
Best ResponseYou've already chosen the best response.0Do you Remember me im the bear guy :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i vaguely recall a screenname like yours; at my age its all i can do to remember to wear socks

gopeder
 3 years ago
Best ResponseYou've already chosen the best response.0xD we talked alot maybe 4 mounts ago

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1yeah, 4 months is an eternity around here lol how you been?

gopeder
 3 years ago
Best ResponseYou've already chosen the best response.0haha so true :) Not much Just starting Geometry.. its loads of fun

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1if you ever meet euclid, punch him in the breadbasket for me. hes to blame for alot of that geometry stuff

gopeder
 3 years ago
Best ResponseYou've already chosen the best response.0But at the end of the day its really cool because it relates to real world

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1Amistre, sorry to bother you guys, but can you take a look at this? please? http://openstudy.com/study#/updates/4f4d9f77e4b019d0ebade348

robtobey
 3 years ago
Best ResponseYou've already chosen the best response.0Refer to the attachment.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1We got "derive" at the college that looks quite similar to that kind of thing.
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