## anonymous 4 years ago Alright, this is an integration calculus problem, multiple choice. (Written out in the next post)

1. anonymous

let K = $\int\limits_{-2}^{3} \sin (x ^{1/3})$ which of the following is then true? 1<k<or=2 2<k<or=3 3<k 0<k<1 k<or=0

2. anonymous

I understand that since sin is an odd function, we can disregard the integral from -2 to 2, as it equals zero. but I don't understand what to do from there. it leaves me with: $\int\limits_{2}^{3} \sin x^{1/2}$

3. anonymous

sorry! in my last post I meant to write the integral of sin (x ^1/3), not x^1/2

4. anonymous

How can you do the substitution if the derivative of x^1/3 isn't there?

5. anonymous

yea i realized :(

6. anonymous

oh :P