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ggrree

  • 2 years ago

Alright, this is an integration calculus problem, multiple choice. (Written out in the next post)

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  1. ggrree
    • 2 years ago
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    let K = \[\int\limits_{-2}^{3} \sin (x ^{1/3})\] which of the following is then true? 1<k<or=2 2<k<or=3 3<k 0<k<1 k<or=0

  2. ggrree
    • 2 years ago
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    I understand that since sin is an odd function, we can disregard the integral from -2 to 2, as it equals zero. but I don't understand what to do from there. it leaves me with: \[\int\limits_{2}^{3} \sin x^{1/2}\]

  3. ggrree
    • 2 years ago
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    sorry! in my last post I meant to write the integral of sin (x ^1/3), not x^1/2

  4. ggrree
    • 2 years ago
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    How can you do the substitution if the derivative of x^1/3 isn't there?

  5. Hermeezey
    • 2 years ago
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    yea i realized :(

  6. ggrree
    • 2 years ago
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    oh :P

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