anonymous
  • anonymous
Say I have a three digit combination lock. What is the minimum number of trials I need on the combination to ensure that I get the correct combination? Hint.. answer is not 10^3 ...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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KingGeorge
  • KingGeorge
If I type in these numbers; 0123456789, will it count as trying all of 012, 123, 234, 345, 456, 567, 678, and 789?
KingGeorge
  • KingGeorge
Or only 012, 345, 678, 9?
anonymous
  • anonymous
012, 345, 678

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KingGeorge
  • KingGeorge
Are there any other restrictions? Otherwise, I don't see how it could be anything but \(10^3\).
campbell_st
  • campbell_st
well there are 10^3 possible combinations... so you could take 10^3 -1 attempts before you get the successful combination
campbell_st
  • campbell_st
that is assuming the correct combination is the last 1 entered
campbell_st
  • campbell_st
then its 9^3 - 1 since only 9 digits
campbell_st
  • campbell_st
so 728 trials may be needed
campbell_st
  • campbell_st
minimum is 1 trial as you get it 1st go
anonymous
  • anonymous
Okk .. I would elaborate the question ... I have a three digit combination lock with each digit having 10 possibilities. Once the correct combination is entered the lock opens automatically. How will I optimize my search so as to ensure that I get the combination in the mimimum number of trials. Whst is the minimum number of trials? None of the answers given so far are correct
campbell_st
  • campbell_st
well you gave us 9 digits 0 to 8
anonymous
  • anonymous
Is this really possible? I mean is there a algorithm for this system which could be faster than the brute force algorithm.

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