Here's the question you clicked on:
OmidV
I will draw diagram, question asks for the rise and slope of the secant line.
|dw:1330580434660:dw| curve is y = 4x^2 + 5x
huh? what do u mean by "chicken" ?
I think he's just goofing around :D Can't blame him, it's 3am here I just want to solve this and then go to bed :P
and then u delete that answer and we all look stupid...
Lol sorry. saso. sorry man ahah im a little tired today so cant blame me for being goofy. excuse my immatureness
well if you couldn't answer it now, no need to have even made a comment in the first place...
Umm If i remeber correctly..Ohh na cant.. umm try googling bro.
Your immaturity* has been excused. Now if you don't mind, discuss your boredom in chat as I would like to solve this.
Have you googled. Google helps me in these situations
this is in a calculus class... right? i know the gradient function to be the first derivative of a curve function... not sure how to find the "rise" though... i suppose that means the height?
i presume this is pre-calculus ?
Yes, the height is the rise. Well, this is my first calculus course in college for computer engineering - computing science. It assumes no previous knowledge of calculus. If that's what pre-calc means then yes.
I remember it had something to do with the y at 2 being f(2), and then the y at 2+h being f(2+h)
It's possible my answer was incorrect because I added instead of subtracted, one moment please.
do you know how to differentiate ?
I recognize the term so probably, I just can't really think of an example atm. It's very late. Here, this is what I think I'm supposed to do to find the rise: y2 - y1, y2 = f(2+h), y1 = f(2). f(2+h) = 4(2+h)^2 + 5(2+h), f(2) = 4(2)^2 + 5(2)
Yeah that's definitely it, I'm not sure how I managed to mess that up during the test.
to find the slope is simply the rise/run
Nice, solved my own question :D does that mean I get a medal for good answer? ;)
Yeah the slope was the "easy" part just divide by h basically.
f(2+h) is the function of the rise... you'll notice that f(2+h) is the y value as the x value = 2+h|dw:1330589766893:dw|
Thanks saso, I got the answer now :D
ok some part of it got missing... \[\huge \frac{f(2+h)-f(2)}{h} \]
yw :) i hope it's clear though
Yup, I figured it out after retrying the question, I guess before I went through the right steps but I had 4h^2 + 13h as opposed to the correct 4h^2 + 21h (for the rise), so it was a calculation error and I assumed I was doing the problem wrong so came here for help :D