I will draw diagram, question asks for the rise and slope of the secant line.

- anonymous

I will draw diagram, question asks for the rise and slope of the secant line.

- jamiebookeater

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- anonymous

|dw:1330580434660:dw| curve is y = 4x^2 + 5x

- sasogeek

huh? what do u mean by "chicken" ?

- anonymous

I think he's just goofing around :D Can't blame him, it's 3am here I just want to solve this and then go to bed :P

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- sasogeek

and then u delete that answer and we all look stupid...

- anonymous

Lol sorry. saso. sorry man ahah im a little tired today so cant blame me for being goofy. excuse my immatureness

- sasogeek

well if you couldn't answer it now, no need to have even made a comment in the first place...

- anonymous

Umm If i remeber correctly..Ohh na cant.. umm try googling bro.

- anonymous

Your immaturity* has been excused. Now if you don't mind, discuss your boredom in chat as I would like to solve this.

- anonymous

Have you googled. Google helps me in these situations

- sasogeek

this is in a calculus class... right? i know the gradient function to be the first derivative of a curve function... not sure how to find the "rise" though... i suppose that means the height?

- EarthCitizen

i presume this is pre-calculus ?

- anonymous

Yes, the height is the rise. Well, this is my first calculus course in college for computer engineering - computing science. It assumes no previous knowledge of calculus. If that's what pre-calc means then yes.

- anonymous

I remember it had something to do with the y at 2 being f(2), and then the y at 2+h being f(2+h)

- anonymous

It's possible my answer was incorrect because I added instead of subtracted, one moment please.

- EarthCitizen

do you know how to differentiate ?

- anonymous

I recognize the term so probably, I just can't really think of an example atm. It's very late. Here, this is what I think I'm supposed to do to find the rise:
y2 - y1, y2 = f(2+h), y1 = f(2). f(2+h) = 4(2+h)^2 + 5(2+h), f(2) = 4(2)^2 + 5(2)

- anonymous

Yeah that's definitely it, I'm not sure how I managed to mess that up during the test.

- EarthCitizen

to find the slope is simply the rise/run

- anonymous

Nice, solved my own question :D does that mean I get a medal for good answer? ;)

- anonymous

Yeah the slope was the "easy" part just divide by h basically.

- sasogeek

f(2+h) is the function of the rise... you'll notice that f(2+h) is the y value as the x value = 2+h|dw:1330589766893:dw|

- anonymous

Thanks saso, I got the answer now :D

- sasogeek

|dw:1330589944341:dw|

- sasogeek

ok some part of it got missing... \[\huge \frac{f(2+h)-f(2)}{h} \]

- anonymous

Thank you saso :)

- sasogeek

yw :) i hope it's clear though

- anonymous

Yup, I figured it out after retrying the question, I guess before I went through the right steps but I had 4h^2 + 13h as opposed to the correct 4h^2 + 21h (for the rise), so it was a calculation error and I assumed I was doing the problem wrong so came here for help :D

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