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cuddlepony

  • 4 years ago

1 C8H9NO3 -> 4 C8H10NO3 to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?

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  1. cuddlepony
    • 4 years ago
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    I'm half asleep I know this but I just need to confirm so I can finish my lab

  2. cuddlepony
    • 4 years ago
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    so if I had 0.00309mol of reactant I would have 0.01236moles of product therefore I would have 2.1g of product?

  3. cuddlepony
    • 4 years ago
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    167g/mol is the molecular mass of the product

  4. sasogeek
    • 4 years ago
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    I'm not good at this but logically that makes sense

  5. cuddlepony
    • 4 years ago
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    I'm a pro at stochiometry but is 4 in the morning lol

  6. cuddlepony
    • 4 years ago
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    so im not a pro at the momment

  7. sasogeek
    • 4 years ago
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    lol k

  8. cuddlepony
    • 4 years ago
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    thanks :) wow I didnt get much of yield at all ugh

  9. sasogeek
    • 4 years ago
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    yw :)

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