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cuddlepony
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1 C8H9NO3 > 4 C8H10NO3
to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?
 2 years ago
 2 years ago
cuddlepony Group Title
1 C8H9NO3 > 4 C8H10NO3 to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?
 2 years ago
 2 years ago

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cuddlepony Group TitleBest ResponseYou've already chosen the best response.0
I'm half asleep I know this but I just need to confirm so I can finish my lab
 2 years ago

cuddlepony Group TitleBest ResponseYou've already chosen the best response.0
so if I had 0.00309mol of reactant I would have 0.01236moles of product therefore I would have 2.1g of product?
 2 years ago

cuddlepony Group TitleBest ResponseYou've already chosen the best response.0
167g/mol is the molecular mass of the product
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.1
I'm not good at this but logically that makes sense
 2 years ago

cuddlepony Group TitleBest ResponseYou've already chosen the best response.0
I'm a pro at stochiometry but is 4 in the morning lol
 2 years ago

cuddlepony Group TitleBest ResponseYou've already chosen the best response.0
so im not a pro at the momment
 2 years ago

cuddlepony Group TitleBest ResponseYou've already chosen the best response.0
thanks :) wow I didnt get much of yield at all ugh
 2 years ago
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