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cuddlepony Group Title

1 C8H9NO3 -> 4 C8H10NO3 to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?

  • 2 years ago
  • 2 years ago

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  1. cuddlepony Group Title
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    I'm half asleep I know this but I just need to confirm so I can finish my lab

    • 2 years ago
  2. cuddlepony Group Title
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    so if I had 0.00309mol of reactant I would have 0.01236moles of product therefore I would have 2.1g of product?

    • 2 years ago
  3. cuddlepony Group Title
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    167g/mol is the molecular mass of the product

    • 2 years ago
  4. sasogeek Group Title
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    I'm not good at this but logically that makes sense

    • 2 years ago
  5. cuddlepony Group Title
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    I'm a pro at stochiometry but is 4 in the morning lol

    • 2 years ago
  6. cuddlepony Group Title
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    so im not a pro at the momment

    • 2 years ago
  7. sasogeek Group Title
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    lol k

    • 2 years ago
  8. cuddlepony Group Title
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    thanks :) wow I didnt get much of yield at all ugh

    • 2 years ago
  9. sasogeek Group Title
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    yw :)

    • 2 years ago
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