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Jacob1407

  • 2 years ago

make L the subject Z=√R^2+(2πFL-1/2πFC)^2

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  1. sasogeek
    • 2 years ago
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    if i'm reading this right, tell me if this is the equation \[\huge z=\sqrt{R^2}+(\large \frac{2\pi FL-1}{2\pi FC}\huge ) \] is this it?

  2. sasogeek
    • 2 years ago
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    and the bracket is raised to the power 2...

  3. angela210793
    • 2 years ago
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    or this one?|dw:1330597835511:dw|

  4. Jacob1407
    • 2 years ago
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    This is correct Angla210793

  5. Jacob1407
    • 2 years ago
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    How can I make L the subject please ?

  6. angela210793
    • 2 years ago
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    |dw:1330597975265:dw|

  7. sasogeek
    • 2 years ago
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    the best way to think of this is to make L stand alone, do whatever it takes :D ;) i believe the steps shown are self explanatory, if u still have issues, let us know :)

  8. Jacob1407
    • 2 years ago
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    |dw:1330598152930:dw|

  9. angela210793
    • 2 years ago
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    no way O.o -_- I asked you if it was like that and u said yes .....

  10. Jacob1407
    • 2 years ago
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    I am sorry angela210793

  11. sasogeek
    • 2 years ago
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    well in this case you'll have |dw:1330598202561:dw| just square both sides to clear the square root then solve from there :)

  12. Jacob1407
    • 2 years ago
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    Please try again angela210793

  13. sasogeek
    • 2 years ago
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    |dw:1330598314446:dw|

  14. NotSObright
    • 2 years ago
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    |dw:1330598398763:dw|

  15. angela210793
    • 2 years ago
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    |dw:1330598452010:dw|

  16. Jacob1407
    • 2 years ago
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    thank so much you guys

  17. Jacob1407
    • 2 years ago
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    thank you so much guys

  18. sasogeek
    • 2 years ago
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    do you get it though?

  19. angela210793
    • 2 years ago
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    |dw:1330598631667:dw|

  20. Jacob1407
    • 2 years ago
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    |dw:1330600973271:dw|

  21. Jacob1407
    • 2 years ago
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    express Ln y as simply as possible

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