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sasogeek
 3 years ago
what's the easiest way to determine whether the binary operation * is associative, if * is defined by \(x*y=\frac{x+y}{1+xy} \)
sasogeek
 3 years ago
what's the easiest way to determine whether the binary operation * is associative, if * is defined by \(x*y=\frac{x+y}{1+xy} \)

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NotSObright
 3 years ago
Best ResponseYou've already chosen the best response.0Define associativity

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0x*(y*z)=(x*y)*z ... if it's associative, then the right hand side should be equal to the left hand side

NotSObright
 3 years ago
Best ResponseYou've already chosen the best response.0It is associative i did it by verifying LHS=RHS Although intuition pointed it right away

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0well is that the easiest way...? i was thinking maybe there's a faster method

Mr.Math
 3 years ago
Best ResponseYou've already chosen the best response.2It clearly follows from the associativity of addition and multiplication.

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0what do u mean by that?

Mr.Math
 3 years ago
Best ResponseYou've already chosen the best response.2I mean \((x*y)*z=\frac{(x+y)+z}{1+(xy)z}=\frac{x+(y+z)}{1+x(yz)}=x*(y*z).\)

sasogeek
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh okay, well i was doing some weird workings but the answer was quite obvious right from the beginning :) thanks
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