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Courtney.soden
Group Title
The formula P=0.64x^20.049+2 models the approx population P, in thousands, for a species of fish in a local pond, x yrs after 1997. During what yr will the population reach 42,568???
2004,2005,2006, or 2007
 2 years ago
 2 years ago
Courtney.soden Group Title
The formula P=0.64x^20.049+2 models the approx population P, in thousands, for a species of fish in a local pond, x yrs after 1997. During what yr will the population reach 42,568??? 2004,2005,2006, or 2007
 2 years ago
 2 years ago

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sasogeek Group TitleBest ResponseYou've already chosen the best response.2
put P=42,568 and solve for x, and then add x to 1997 to find the answer
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
So solve for P first than add x to 42,568?
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.2
noo, the population is equalto 42,568 in a certain year, that's what we want to find... that year. to get that year, we know that x is the number of years after 1997 for which the population will be equal to 42,568... so we find x and add it to 1997 and voila, we know the year. :) is that making any sense so far?
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
so 42,568=0.64x^20.049x+2 is the equation right? I think thats what I understood by what you just wrote
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.2
exactly... then we find x
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
I got x as 42,29,and 29
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
no that is not the right equation i don't think, because it gives the population in thousands
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
Well Mr. Satellite73 help plz [=
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
try this one \[ 42.568 = 0.64 x^20.049+2\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=42.568%3D0.64x%5E20.049%2B2
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
looks like the answer is closest to x = 8 so 8 years after 1997
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
aka 2005
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
Thank you [=
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.2
I think she missed the x after the 0.049 in her original question cos i noticed she wrote that in her reply.... so that makes it a quadratic, but i could be wrong
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
Yeah I missed the x after 0.049x
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.2
and btw why did u write 42.568 <<< and not 42,568 ?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
because it says it gives the answer in thousands so if you get P = 4 that means 4,000
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the answer appears to be 8 i redid it http://www.wolframalpha.com/input/?i=42.568%3D0.64x%5E20.049x%2B2
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.2
yeah it is, i solved it and it's approximately 8 so yeah :)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
wolfram says 8 when i redid it
 2 years ago

Courtney.soden Group TitleBest ResponseYou've already chosen the best response.0
Gracias you guys I loved the help
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.2
anytime :)
 2 years ago
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