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x=−b±(√b2−4ac)/2a

aaaaa what's that ? i don't think that's the way

this will give u two value for x..........& say it x1,x2......
now factor is (x-x1)(x-x2)...ok

|dw:1330616930509:dw|

what??!! no no!

(b-6) (3b-2) am i right ?

Sorry it'd be
\[(x-(\frac{10+ 2\sqrt{34}}{3}))(x-(\frac{10 -2\sqrt{34}}{3}))\]
I missed the 2:(

ah that's too advance i guess but right factors (b-6)(3b-2)

yah :) do u know how to get (b-6)(3b-2)