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kanigayanBest ResponseYou've already chosen the best response.0
aaaaa what's that ? i don't think that's the way
 2 years ago

amitlpu91Best ResponseYou've already chosen the best response.0
this will give u two value for x..........& say it x1,x2...... now factor is (xx1)(xx2)...ok
 2 years ago

kanigayanBest ResponseYou've already chosen the best response.0
dw:1330616930509:dw
 2 years ago

kanigayanBest ResponseYou've already chosen the best response.0
(b6) (3b2) am i right ?
 2 years ago

ash2326Best ResponseYou've already chosen the best response.1
we have \[3b^220b12\] standard quadratic equation \[ax^2+bx+c=0\] we know its solution is given as \[x=\frac{b\pm \sqrt{b^24ac}}{2a}\] here a=3 b=20 and c=12 so \[x=\frac{(20)\pm \sqrt{(20)^24\times 3\times 12}}{2\times 3}\] we get \[x=\frac{20\pm \sqrt{400+144}}{6}\] now we get \[x=\frac{20\pm \sqrt{400+144}}{6}\] we get \[x=\frac{20\pm \sqrt{544}}{6}\] \[544= 17\times 16\times 2\] so \[x=\frac{20\pm \sqrt{16\times 34}}{6}\] we get \[x=\frac{20\pm 4\sqrt{ 34}}{6}\] let's divide by 2 \[x=\frac{10\pm \sqrt{34}}{3}\] so the two factors are \[(x(\frac{10+ \sqrt{34}}{3}))(x(\frac{10 \sqrt{34}}{3}))\]
 2 years ago

ash2326Best ResponseYou've already chosen the best response.1
Sorry it'd be \[(x(\frac{10+ 2\sqrt{34}}{3}))(x(\frac{10 2\sqrt{34}}{3}))\] I missed the 2:(
 2 years ago

kanigayanBest ResponseYou've already chosen the best response.0
ah that's too advance i guess but right factors (b6)(3b2)
 2 years ago

ash2326Best ResponseYou've already chosen the best response.1
No, these are not the factors \[ (b6)(3b2)= 3b^220b+12\] but in your question you have \[3b^220b12\]
 2 years ago

kanigayanBest ResponseYou've already chosen the best response.0
yah :) do u know how to get (b6)(3b2)
 2 years ago
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