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Tia1977

  • 4 years ago

hi JuanitaM. can I have your help on a problem?

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  1. mariomintchev
    • 4 years ago
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    Tag her

  2. mariomintchev
    • 4 years ago
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    @JuanitaM

  3. Tia1977
    • 4 years ago
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    how do i do that?

  4. mariomintchev
    • 4 years ago
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    press @ and type the name

  5. mariomintchev
    • 4 years ago
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    its like facebook

  6. Tia1977
    • 4 years ago
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    ok thanks.

  7. JuanitaM
    • 4 years ago
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    hi

  8. JuanitaM
    • 4 years ago
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    i will definitely try :) Go for it

  9. Tia1977
    • 4 years ago
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    Hi, Im sorry i don't how to tag.

  10. Hero
    • 4 years ago
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    @Tia1977

  11. Hero
    • 4 years ago
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    Just put @ symbol afront their name.

  12. Tia1977
    • 4 years ago
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    you work a problem for me 2 days ago. I am reviewing the notes for better understanding and a question arose. should i repost the problem? or can you view it.

  13. Hero
    • 4 years ago
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    Whatever the question is, just post it.

  14. JuanitaM
    • 4 years ago
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    yea pls repost

  15. Tia1977
    • 4 years ago
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    okay. 2x(x-3)=3x+2--- this is completing the square.

  16. JuanitaM
    • 4 years ago
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    I see

  17. Tia1977
    • 4 years ago
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    I got confused on how you got the 97/

  18. Tia1977
    • 4 years ago
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    my math could be off but i couldn't follow

  19. JuanitaM
    • 4 years ago
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    |dw:1330628200793:dw|

  20. iloveboys
    • 4 years ago
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    Hey, help me when you get the chance. Thanks you so much.

  21. JuanitaM
    • 4 years ago
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    ok - so first lets remove the parenthesis and get all terms with x on one side. so do you follow me up to that line above

  22. Tia1977
    • 4 years ago
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    yes

  23. JuanitaM
    • 4 years ago
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    |dw:1330628303344:dw|

  24. JuanitaM
    • 4 years ago
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    note that for completing the square there can not be ANY coeffficient in front of x^2 so divide EACH term to remove the coefficient ....

  25. Tia1977
    • 4 years ago
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    ok

  26. JuanitaM
    • 4 years ago
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    |dw:1330628383084:dw|

  27. JuanitaM
    • 4 years ago
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    now to get the square of a fraction - you are basicallly multiply by 1/2 and that is where the 9/4 came from..... follow?

  28. Tia1977
    • 4 years ago
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    yes.

  29. JuanitaM
    • 4 years ago
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    |dw:1330628466651:dw|

  30. Tia1977
    • 4 years ago
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    i got lost in the step that follow this one

  31. JuanitaM
    • 4 years ago
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    so hear - you must ADD the square on both sides. hence the (9/4)^2 on both sides ..... right?

  32. Tia1977
    • 4 years ago
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    ok.

  33. JuanitaM
    • 4 years ago
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    on the left side you must add fraction by putting over common denomiator =

  34. JuanitaM
    • 4 years ago
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    |dw:1330628635863:dw|

  35. JuanitaM
    • 4 years ago
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    you follow?

  36. Tia1977
    • 4 years ago
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    the 16/16? confusing

  37. Tia1977
    • 4 years ago
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    o i c it now. duh!!

  38. JuanitaM
    • 4 years ago
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    |dw:1330628767788:dw|

  39. JuanitaM
    • 4 years ago
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    LOL - good :)

  40. Tia1977
    • 4 years ago
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    thank soo much.

  41. JuanitaM
    • 4 years ago
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    do you have any other questions or was that the issue?

  42. Tia1977
    • 4 years ago
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    that was the only issue. thanks again.

  43. JuanitaM
    • 4 years ago
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    Np - thanks for looking me up. Anytime. :) keep up the good work - C u later

  44. Tia1977
    • 4 years ago
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    toodles.

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