anonymous
  • anonymous
Four cows are tied with a rope of length 7 cm at four corners of a quadrilateral field of unequal sides. Find the total area grazed.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Won't it be equal to a full circle of radius 7 cm????
anonymous
  • anonymous
This question seems a little ambiguous, but I'll give it a try. Cut the quad in half which will result in 2 triangles. The hypotenuse of both triangles is going to be 14. It doesn't matter how long each side is since the area will be the same for each. Remember pathagorean's therom? A^2 + B^2 = C^2. C is the hypotenuse and we can assume that A = B. We can transform this equation into squrt(14) = 2A^2. We divide both sides by 2 and get squrt(14)/2= A^2. Now square root that again which becomes 14^(1/4)/2^(1/2) = A. Now all you do to find the are is square A which becomes squrt(14)/2. I'm pretty sure it's right, but I wouldn't count on stranger's advice from the internet.
anonymous
  • anonymous
@dunn0053 thanks for the try..............but it is not correct Now, i am quite sure about my solution that the area is equal to the area of a full circle of radius 7 cm....☺

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anonymous
  • anonymous
Well then the area would be pi * r^2 which is 49pi, but I dunno that the answer would be a circle if they talk about quadrilaterals in the question.
anonymous
  • anonymous
My logic is simple and easy to understand...... the sum of the four interior angles of a quadrilateral is always 360 degree so all the four angles will total up to 360 but they will be in sectors of different angles but all will have radius 7 cm so when you put them all together, they will form a full circle because a circle = 360 degree so the answer is πr^2 = 3.14*49cm^2 = 153.86 cm^2
anonymous
  • anonymous
|dw:1330677206877:dw| \[\theta 1 / 360 \times \pi r ^{2} + \theta2 / 360 \times \pi r ^{2} +\]\[\theta3/ 360 \times \pi r ^{2} +\theta4 / 360 \times \pi r ^{2}\] \[= (\theta1 /360+ \theta2 /360 + \theta3/360 + \theta 4/360) \times \pi r ^{2}\] \[=( \theta1 +\theta2 +\theta3 +\theta4)/360 \times \pi r ^{2}\] \[= 360/360 \times \pi r ^{2}\] \[= \pi r ^{2}\] = (22/7) *7 *7 = 22 * 7 = 154 unit sq.
anonymous
  • anonymous
that is what I said sunjeet95.....☺ anyway....medal for yr effort
anonymous
  • anonymous
thanxx

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