AcidRa1n
Area of trapezoid
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AcidRa1n
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AcidRa1n
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I know the answer is D
AcidRa1n
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Its something with 45 30 90 or something that one angle on the left
saifoo.khan
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\[\frac12\times base \times \text{(s um of p arallel sides)}\]
AcidRa1n
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you use the 1/2h (b1+b2)
saifoo.khan
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Yes.
saifoo.khan
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But we have to find the value of the line adjacent with 45*/
AcidRa1n
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Yeah how its something with 45 30 90 or something my teacher said i forgot
saifoo.khan
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Use tan ratio to find it.
saifoo.khan
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\[\tan \theta = \frac{opp}{adj}\]
\[\tan 45 = \frac{7}{adj}\]
\[adj = 7\]|dw:1330659614940:dw|
saifoo.khan
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Now you have all the values,
\[\frac12 * 7 * (8+8+3+7)\]Solve.:)
AcidRa1n
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ohh its 7
why do you use tan?
saifoo.khan
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Because we have to choose either one of the three ratios..
If you feel confusion, try writing the 2 other ratios as well.. And try applying them.
Later you will find that u can't use those here.
AcidRa1n
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oh alright thanks, got a big test tomorrow!
saifoo.khan
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Best of luck.
Believe me, i too used to get confused b/w which one to use.. then i found a shortcut. ;)