kenny97701 Group Title for f(x)^2 compute and simplify the difference quotient f(x+h)-f(x)/h. I ended up with f(x)=0. is this correct? 2 years ago 2 years ago

1. sasogeek Group Title

how did u arrive at f(x)=0 ?

2. kenny97701 Group Title

basically by canceling out the h and 5x^2

3. Dockworker Group Title

what is f(x)

4. sasogeek Group Title

did you mean f(x)=x^2 ? cos i don't see how you can start working that out if you haven't defined f(x) in the first place :/

5. kenny97701 Group Title

f(x)=5x^2

6. kenny97701 Group Title

sorry

7. Dockworker Group Title

you have to substitute (x+h) for x in f(x+h), you're not going to end up with 0

8. sasogeek Group Title

ok so you'll do what Dockworker said and you'll end up with this. $\huge \frac{5(x+h)^2-5x^2}{h}$$\huge \text{simplify that and I believe that'd be it :) }$

9. kenny97701 Group Title

thats what i thought. thanks

10. sasogeek Group Title

anytime :)