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Rogue Group TitleBest ResponseYou've already chosen the best response.1
This seems like an interesting little problem...\[y = \lim_{x \rightarrow \frac {\pi}{2}} (\sin x)^{\tan x}\]\[\ln y = \ln \lim_{x \rightarrow \frac {\pi}{2}} (\sin x)^{\tan x} \rightarrow \ln y = \lim_{x \rightarrow \frac {\pi}{2}} \tan x \ln (\sin x)\]\[\ln y = \lim_{x \rightarrow \frac {\pi}{2}} \tan x \ln (\sin x) \rightarrow \ln y = \lim_{x \rightarrow \frac {\pi}{2}} \frac {\sin x \ln (\sin x)}{\cos x} = \frac {0}{0}\]
 2 years ago

Rogue Group TitleBest ResponseYou've already chosen the best response.1
Now you'll have to use L'Hopital's rule to evaluate that. Can you do that or need me to run you through it?
 2 years ago

suju101 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow \infty} (lnx)^{1/x}\] can you please help me with this probelm too..
 2 years ago
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