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viniterranova

  • 4 years ago

x=sqrt(7+4sqrt3)+sqrt(7-4sqrt3)

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  1. viniterranova
    • 4 years ago
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  2. viniterranova
    • 4 years ago
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    You may see the equation here.

  3. ash2326
    • 4 years ago
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    We have \[x=\sqrt{7+4\sqrt 3}+\sqrt{7-4\sqrt 3}\] Let's multiply and divide this by \(\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}\) we have \[x=\sqrt{7+4\sqrt 3}+\sqrt{7-4\sqrt 3} \times \frac{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\] We get \[x=\frac{{(\sqrt{7+4\sqrt 3})^2 }-(\sqrt{(7-4\sqrt 3})^2 }{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\] we get \[x=\frac{7+4\sqrt 3-(7-4 \sqrt 3)}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\] so we get \[x=\frac{8\sqrt 3}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\]

  4. viniterranova
    • 4 years ago
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    Is this the answer?

  5. ash2326
    • 4 years ago
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    Yeah can't be simplified more

  6. viniterranova
    • 4 years ago
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    How it be made?

  7. viniterranova
    • 4 years ago
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    Because the answer is 4.

  8. Elodi
    • 4 years ago
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    Ai Se Eu Te Pego -

  9. Elodi
    • 4 years ago
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    159

  10. viniterranova
    • 4 years ago
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    rrsrsrs

  11. Elodi
    • 4 years ago
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    good

  12. viniterranova
    • 4 years ago
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    De onde vc é Elodi?

  13. Elodi
    • 4 years ago
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    quoi

  14. viniterranova
    • 4 years ago
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    Vc falou português

  15. viniterranova
    • 4 years ago
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    i m from Brazil

  16. Elodi
    • 4 years ago
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    okk

  17. viniterranova
    • 4 years ago
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    or u may send me your link profile

  18. ash2326
    • 4 years ago
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    I got it, Let me show you how this 4

  19. Elodi
    • 4 years ago
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    yes]

  20. ash2326
    • 4 years ago
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    @viniterranova please don't share personal info like facebook id here. Delete it please

  21. viniterranova
    • 4 years ago
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    ok

  22. viniterranova
    • 4 years ago
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    Bye Elodi See u around i ve got go

  23. Elodi
    • 4 years ago
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    y

  24. ash2326
    • 4 years ago
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    We have \[x=\sqrt {7+4 \sqrt 3}+\sqrt {7-4 \sqrt 3}\] Let's square both the sides we get \[x^2=(\sqrt {7+4 \sqrt 3})^2+(\sqrt {7-4 \sqrt 3})^2+2\times (\sqrt {7+4 \sqrt 3})\times (\sqrt {7-4 \sqrt 3})\] we get \[x^2=7+4\sqrt 3+7-4\sqrt 3+2 \sqrt{(7^2-(4\sqrt 3)^2}\] we get \[x^2=14+2\times \sqrt {49-16\times 3}\] we get \[x^2=14+2\times \sqrt 1\] we get \[x^2=14+2=16\] so \[x=4\]

  25. Bhavnazoon
    • 4 years ago
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    square on both sides|dw:1330781973743:dw|

  26. viniterranova
    • 4 years ago
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    Good.

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