anonymous
  • anonymous
x=sqrt(7+4sqrt3)+sqrt(7-4sqrt3)
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
You may see the equation here.
ash2326
  • ash2326
We have \[x=\sqrt{7+4\sqrt 3}+\sqrt{7-4\sqrt 3}\] Let's multiply and divide this by \(\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}\) we have \[x=\sqrt{7+4\sqrt 3}+\sqrt{7-4\sqrt 3} \times \frac{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\] We get \[x=\frac{{(\sqrt{7+4\sqrt 3})^2 }-(\sqrt{(7-4\sqrt 3})^2 }{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\] we get \[x=\frac{7+4\sqrt 3-(7-4 \sqrt 3)}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\] so we get \[x=\frac{8\sqrt 3}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Is this the answer?
ash2326
  • ash2326
Yeah can't be simplified more
anonymous
  • anonymous
How it be made?
anonymous
  • anonymous
Because the answer is 4.
anonymous
  • anonymous
Ai Se Eu Te Pego -
anonymous
  • anonymous
159
anonymous
  • anonymous
rrsrsrs
anonymous
  • anonymous
good
anonymous
  • anonymous
De onde vc é Elodi?
anonymous
  • anonymous
quoi
anonymous
  • anonymous
Vc falou português
anonymous
  • anonymous
i m from Brazil
anonymous
  • anonymous
okk
anonymous
  • anonymous
or u may send me your link profile
ash2326
  • ash2326
I got it, Let me show you how this 4
anonymous
  • anonymous
yes]
ash2326
  • ash2326
@viniterranova please don't share personal info like facebook id here. Delete it please
anonymous
  • anonymous
ok
anonymous
  • anonymous
Bye Elodi See u around i ve got go
anonymous
  • anonymous
y
ash2326
  • ash2326
We have \[x=\sqrt {7+4 \sqrt 3}+\sqrt {7-4 \sqrt 3}\] Let's square both the sides we get \[x^2=(\sqrt {7+4 \sqrt 3})^2+(\sqrt {7-4 \sqrt 3})^2+2\times (\sqrt {7+4 \sqrt 3})\times (\sqrt {7-4 \sqrt 3})\] we get \[x^2=7+4\sqrt 3+7-4\sqrt 3+2 \sqrt{(7^2-(4\sqrt 3)^2}\] we get \[x^2=14+2\times \sqrt {49-16\times 3}\] we get \[x^2=14+2\times \sqrt 1\] we get \[x^2=14+2=16\] so \[x=4\]
anonymous
  • anonymous
square on both sides|dw:1330781973743:dw|
anonymous
  • anonymous
Good.

Looking for something else?

Not the answer you are looking for? Search for more explanations.