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AmberK

  • 2 years ago

Mike is saving money for his first car. He already saved $300 from cutting grass last summer. He has an after school job and saves $250 from his paychecks every month. This relationship is represented by the equation y = 250x + 300, where x is the number of months and y is the cost of the car. 1. Identify the slope (m) in this relationship. 2. Explain what the slope (m) means in this situation. 3. Identify the y-intercept (b) in this relationship. 4. Explain what the y-intercept (b) means in this situation. 5. Use the equation to determine the number of months Mike will nee

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  1. brinethery
    • 2 years ago
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    Slope: 250

  2. brinethery
    • 2 years ago
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    For every month he works, he makes $250

  3. brinethery
    • 2 years ago
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    y-intercept: 300

  4. brinethery
    • 2 years ago
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    meaning: the initial amount of money he had starting out was $300.

  5. brinethery
    • 2 years ago
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    5. is cut off.

  6. AmberK
    • 2 years ago
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    5. Use the equation to determine the number of months Mike will need to save for a car that costs $4000. 6. Use the equation to determine the maximum amount of money Mike can afford to spend on a car if he saves for 12 months. 7. Explain how the amount of time Mike will take to save for his $4000 car will change if he increased the amount of money he saved each month. 8. Explain how the amount of time Mike will take to save for his $4000 car will change if he decreased the amount of money he saved each month.

  7. brinethery
    • 2 years ago
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    5. 4000 = 250x+300. Solve for x. Your answer will be in months. 6. y = 250(12) +300

  8. brinethery
    • 2 years ago
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    7. Lol he would be able to afford the car faster! 8. It would take longer to save up for the car. (too bad 7 and 8 aren't more specific).

  9. AmberK
    • 2 years ago
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    Thanks For Helping me I was Sooo Confused. (;

  10. brinethery
    • 2 years ago
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    Do you have a good resource as far as your textbook goes?

  11. AmberK
    • 2 years ago
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    Nooopeee.

  12. brinethery
    • 2 years ago
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    Okay lemme see what I can do about that.

  13. AmberK
    • 2 years ago
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    okay.

  14. brinethery
    • 2 years ago
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    when I took algebra 7 years ago, my book was a total piece of pellet.

  15. brinethery
    • 2 years ago
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    Paul's notes have always helped me for calculus and maybe the algebra ones will help for you: http://tutorial.math.lamar.edu/Classes/Alg/Graphing.aspx

  16. brinethery
    • 2 years ago
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    hahaha they censor on here!

  17. AmberK
    • 2 years ago
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    Haha(: Thanks

  18. brinethery
    • 2 years ago
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    So for this problem, your output (y) is in dollars and your input (x) is in months. So if they say if the amount is however many dollars, you know that you have to plug that in to y. If ask something about months, then you plug that into x.

  19. AmberK
    • 2 years ago
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    When i solve for x on this problem 4000 = 250x+300. do i do 250+300 ?

  20. brinethery
    • 2 years ago
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    4000 - 300 = 250x 3700 = 250x (3700/250) = (250x/250) 3700/250 = x

  21. AmberK
    • 2 years ago
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    Okay.

  22. brinethery
    • 2 years ago
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    x = 14.8 months. But we're going to round up. So x= about 15 months

  23. AmberK
    • 2 years ago
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    15 months

  24. brinethery
    • 2 years ago
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    Does input and output stuff make sense to you?

  25. AmberK
    • 2 years ago
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    yeah i get it now.

  26. AmberK
    • 2 years ago
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    Yeah Our books Now Aree Stupid too

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