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ohbev

(3/x)+(13/x-11)

  • 2 years ago
  • 2 years ago

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  1. astrid
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    so i guess you can put them as porportion correct?

    • 2 years ago
  2. ohbev
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    this is what i got for the answer (16x-20)/(x-11) (x+1)

    • 2 years ago
  3. astrid
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    oh i have it different= im going to draw it out for you to see

    • 2 years ago
  4. razor99
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    • 2 years ago
  5. astrid
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    |dw:1330797785578:dw|

    • 2 years ago
  6. astrid
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    x=-0.68

    • 2 years ago
  7. ohbev
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    you have to get the bottoms the same?

    • 2 years ago
  8. razor99
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    @ohbev check my answer

    • 2 years ago
  9. astrid
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    well since im want to know what x is then you dividde 16 on both sides and then you put x= -11/16 that make x=-0.68

    • 2 years ago
  10. astrid
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    @razor99 how did you get that explain plis, i want to know

    • 2 years ago
  11. astrid
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    @ohbev do you understand what i am saying?

    • 2 years ago
  12. ohbev
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    wouldn't you times both fractions so you can combined the bottom terms ?

    • 2 years ago
  13. ohbev
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    well lets see if I'm doing this right in general if (t^2 +6t)/t-1 - 7/t-1 = t+7?

    • 2 years ago
  14. astrid
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    so put it this way.3x= 13x-11, thenyou add the 2 like terms 3x+13x= 16x=-11 then you would divide the 16 because you want to know what x means, so its x=-11/16 then you just calculate it and that would = to -0.68 got it now?

    • 2 years ago
  15. astrid
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    i got to go,...

    • 2 years ago
  16. razor99
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    http://www.wolframalpha.com/input/?i=%283%2Fx%29%2B%2813%2Fx-11%29

    • 2 years ago
  17. razor99
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    @ohbev sld u take a look at that site

    • 2 years ago
  18. razor99
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    i mean cld

    • 2 years ago
  19. ohbev
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    (t^2 +6t)/(t-1) - (7)/(t-1) = t+7?

    • 2 years ago
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