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kirihara

  • 4 years ago

What is the 19th term of the arithmetic sequence 14, 22, 30, … ?

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  1. FoolForMath
    • 4 years ago
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    14+18 \times 8 = 14 + 144 = 158

  2. FoolForMath
    • 4 years ago
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    \[ 14+18 \times 8 = 14 + 144 = 158 \]

  3. madscientist101
    • 4 years ago
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    6+8x where x is the term.

  4. madscientist101
    • 4 years ago
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    6+8(19) 6+152 158

  5. madscientist101
    • 4 years ago
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    The 19th term is therefor 158 :)

  6. FoolForMath
    • 4 years ago
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    @madscientist101: Can you explain?

  7. kirihara
    • 4 years ago
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    thank you!! totally diff than how my teacher showed me haha your way is easier lol

  8. FoolForMath
    • 4 years ago
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    *6+8x @madscientist101

  9. madscientist101
    • 4 years ago
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    that's what I wrote FFM 6+8x

  10. thunderemperor
    • 4 years ago
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    \[T _{n}=a+(n-1)d\] a=14 \[T _{2}=a+(2-1)d=22\] a+d=22 d=22-14=8 \[T _{19}=14+(19-1)8=158\]

  11. FoolForMath
    • 4 years ago
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    Okay, so you go 1 term back and find the 20th term instead of 19th right? @madscientist101

  12. madscientist101
    • 4 years ago
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    The difference between each term is 8. It starts with 14 so it must be 14+8(x-1)... because the you don't want the 14 to be counted as the first term.. although it is... 14+8(x-1) = 14+8x-8 =6+8x @Foolformath

  13. FoolForMath
    • 4 years ago
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    lol nice Mad :)

  14. madscientist101
    • 4 years ago
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    lol yup

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