## kirihara Group Title What is the 19th term of the arithmetic sequence 14, 22, 30, … ? 2 years ago 2 years ago

1. FoolForMath Group Title

14+18 \times 8 = 14 + 144 = 158

2. FoolForMath Group Title

$14+18 \times 8 = 14 + 144 = 158$

6+8x where x is the term.

6+8(19) 6+152 158

The 19th term is therefor 158 :)

6. FoolForMath Group Title

7. kirihara Group Title

thank you!! totally diff than how my teacher showed me haha your way is easier lol

8. FoolForMath Group Title

that's what I wrote FFM 6+8x

10. thunderemperor Group Title

$T _{n}=a+(n-1)d$ a=14 $T _{2}=a+(2-1)d=22$ a+d=22 d=22-14=8 $T _{19}=14+(19-1)8=158$

11. FoolForMath Group Title

Okay, so you go 1 term back and find the 20th term instead of 19th right? @madscientist101

The difference between each term is 8. It starts with 14 so it must be 14+8(x-1)... because the you don't want the 14 to be counted as the first term.. although it is... 14+8(x-1) = 14+8x-8 =6+8x @Foolformath

13. FoolForMath Group Title