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Testing for convergence or divergence of an integral: Use the direct comparison test or limit comparison test to test the integral for convergence.
integral (0 to 1) of dt/(tsint)
How do I know which test to use, and how should I proceed from there?
 2 years ago
 2 years ago
Testing for convergence or divergence of an integral: Use the direct comparison test or limit comparison test to test the integral for convergence. integral (0 to 1) of dt/(tsint) How do I know which test to use, and how should I proceed from there?
 2 years ago
 2 years ago

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RogueBest ResponseYou've already chosen the best response.1
I wish I had my calculator on me :( Try comparing it to 1/t.
 2 years ago

purplemouseBest ResponseYou've already chosen the best response.0
does it matter whether I compare it to 1/t versus 1/t^2 or 1/t^3, etc?
 2 years ago

RogueBest ResponseYou've already chosen the best response.1
Yep, this diverges ;) 1/(t  sin t) > 1/t from t:[0,1] \[\int\limits_{0}^{1} \frac {dt}{t} = \left[ \ln t \right]_{0}^{1}\] That is divergent. Since 1/t (the smaller function) diverges, then 1/(t sin t) (the bigger function) must diverge as well.
 2 years ago

RogueBest ResponseYou've already chosen the best response.1
It doesn't matter for this case, but for other integrals, you might wanna choose carefully.
 2 years ago

purplemouseBest ResponseYou've already chosen the best response.0
I see. thanks. Could I use LCT for this integral as well?
 2 years ago
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