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WHO LIKES CHICKEN NUGGETS? help with writing a c++ program that outputs diff combinations of chicken nugget packs...

Computer Science
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the problem is the nuggets come in packs of 6 9 and 20 and i have to make a program that outputs the different pack combinations that the user can buy for an order. for example,
have you written any code for it?
if the user wanted 54 nuggets, they could have nine packs of six or five packs of nine.

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Other answers:

*six packs of nine.
Ohhh i see
and yeah i didnt write code yet. i am still stuck on making a plan...
this is like finding the factors...
pulling up old codes for ideas...
this is pset2 from 6.00 and i have done it.
do i have to do something with the %.
no, first try to write a simple code or read the problem again
ummm. i am so stuck. do i just write out all the combinations myself ?
oh and there is a cap of 100.
i am not able to tell you clearly about it since you have not written any code.
ok let's start with basics: #include using namespace std; int main() { int amt; cout << "How many nuggets would you like to purchase?" << endl; cin >> amt; ...... hmm now
oh btw the user has to buy something that's a multiple of these. I mean what if he buys less than 6, or what if he buys 7, or 8, etc.
then it cannot be bought
So i guess we could add the following: do { cout << "Please choose a different number: " cin >> ant; } while (a%6!=0 || a%9!=0 || a%20!=0 );
#include #include using namespace std; void main() { int p6, p9, p20, order; cout<<"How many nuggets would you like to order?"; cin>>order; p20=order/20; cout<
lol that's like... *facepalm*
you guys are using c++, but i wrote it in python
this is why i need help.
jask, give me the algorithm, i'll try to translate it.
ok i'll give you the most basic version of this program
here """To find the sizes of McNuggets packages""" from math import * number = input("Enter the number of McNuggets you want to buy :") a=b=c=1 available = True while available == True: a1=number/a + 1 b1=number/b + 1 c1=number/c + 1 for a in range(0,a1): for b in range(0,b1): for c in range(0,c1): if number == 6*a + 9*b + 20*c : print "you need",a,"number of",6,"packs" print "you need",b,"number of",9,"packs" print "you need",c,"number of",20,"packs" print "of McNuggets" print "---------------------------" available=False print "Thank you for Buying and Have a nice day!!!" break
this for the first time i wrote it, a long time ago
it may not be that much elegant but it works, not for every input
okay so why are we dividing by the variable plus 1?
oh boy, i hoped it would work for all inputs, i mean come on, i can write out like 50 if else statements too for all possible inputs..
that ^^
there's no way in heck im doin that lol.. let me think
okay i see...
at least 6 9 and 20 multiples can be done with, for example, an if (order%6==0) p6=order/6; cout<
writing the code in a compiler.. not sure if the right idea.. just yet
okay @bahrom7893 this solution is only for this specific problem, i also have a more general solution
I wish i could've helped you with the code, but still i found this http://en.wikipedia.org/wiki/Coin_problem#McNugget_numbers hope that helps!
is that federer?
aw thankss.
mehh my method didnt work
in fact this program can be generalized too, just take input three packet sizes from user and replace them with 6, 9, 20 and there you have it.
so ask the user to guess first?
the packet sizes as well as the number of mcnuggets they want.
@bahrom7893 Yep, Roger Federer :D
This problem (albeit in python) is on one of the problem sets for course 6.00, problem set 2 to be precise. So you might want to ask there. I've done it, and could give you my code, but it's really basically the same as jaskaran's.
the reason you divide by the variable is because, for example, if you have a box of nuggets with 20 pieces, you know that the maximum number of boxes you could have (and thus the maximum you need to test) is your target/20. As for the +1, it's because the python range function gives you numbers until one behind the number you input, e.g.: range (0,5) 0, 1, 2, 3, 4 C++ may or may not be similar.
does python solve for a b and c in that equation num==2*a + 9*b + 20*c ? cause i dont think c++ does .
okay i am trying to understand jaskarans program...if the input was 6, then how would it print b and c as 0 if they were initialized as 1 ?
I think the reason he put in the line a=b=c=1 is just to initialize them as numbers. But actually I don't think it really matters, since either way you're simply looking at a, b and c values iterated between 0 and number/(size of nugget box). I'll paste my code for it, as upon second look mine is a little different (I don't use a while loop for example) and a bit simpler, and also mine has annotations that might make it more easy to understand. Anyway, here's mine: http://pastebin.com/dpJuFujR Actually I disagree with jaskarans' use of the while loop because, upon a cursory glance, it seems to be irrelevant: the value starts as true, the for statements run, and then the value is false. The program would run just as well without any while statement. As for what you asked, no, python doesn't actually solve (algebraically) the equation as you said. I'm sure you can write a program that solves algebraic equations, but the much more simple answer when dealing with a program language is to use what a computer is good at: trying out a bunch of stuff at blazing speed and testing if it's the right answer.
As a matter of fact, looking back at my program now, the S=0 M=0 L=0 statements I made at the beginning are also irrelevant. S, M, and L values are chosen by the for function, so even if I had not mentioned them at all in the beginning it still wouldn't matter.
i guess python and c++ work differently because i tried translating yours and it is giving me a neverending loop. i am not sure c++ is capable of checking the range by itself.. idk. thanks though !
This is naturally a recursive problem, and since it's a Sunday evening and I'm bored, I wrote this little hack that solves your problem: http://ideone.com/2iYBp
@pre-algebra It works! But not for all inputs. Also please could you explain this part http://ideone.com/01WcK Thanks!
jesssica - there shouldn't be any possibility of an infinite loop occurring with only for statements; they have a strict beginning and end. Or at least, Python is that way and I would assume C++ is as well. Are you sure you're not using a while statement or other loop-generating code?
thanks everyone, i ended up using mod and an else of subtracting from the initial and remainders.

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