bahrom7893
Zarkon, more series help needed :/
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Hero
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bahrom, you keep asking for serious help :P
bahrom7893
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Sorry to bother u guys, but i've been working on series non stop for the whole day today, and i can't really solve theoretical stuff right now - only computational. How would I do this question?
bahrom7893
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bahrom7893
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@Zarkon another one!
Zarkon
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\[a_n=\frac{1}{n}\]
\[\sum_{n=1}^{\infty}\left[\frac{1}{n+1}-\frac{1}{n}\right]\]
\[s_n=\frac{1}{2}-\frac{1}{1}+\frac{1}{3}-\frac{1}{2}+\cdots...\frac{1}{n+1}-\frac{1}{n}\]
\[s_n=-1+\frac{1}{n+1}\]
\[s_n\to -1\text{ as }n\to\infty\]
but \[\sum_{n=1}^{\infty}\frac{1}{n}=\infty\]
bahrom7893
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ty guys!
Hero
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bahrom, what course are you taking?
bahrom7893
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this is not mine, im helping a friend. This is calc 2.. I forgot so much stuff lol, and that was only 2 yrs ago.
Pippa
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hahahaha
bahrom7893
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one more series incoming zarkon
Hero
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Pippa, is something funny?
Pippa
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Yes lol
Hero
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Would you mind sharing the joke with the rest of us? I didn't get it.
Pippa
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haha most things that i think r funny nobody else does
Hero
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You didn't answer my question.
Pippa
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umm meaning i dont want to share it
Hero
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Well, you should have laughed to yourself then. Why share the laugh and not the joke?
bahrom7893
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LOL
Pippa
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hmmm sorry abt that
Pippa
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haha bahrom laughed at that
ParthKohli
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@samjordon what a coincidence that we are viewing this at the same time
ParthKohli
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3 people on such an old question? o.O
samjordon
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who is 3?
ParthKohli
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Ishaan was....he left
samjordon
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ohhhh lol this was one of my old questions so i recognized it
ParthKohli
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Lol why are you on this question btw?
samjordon
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hahahah cuz i saw u on these zarkon last question and all these series questions. Like it appeared next to ur name and i recognized them as mine so i followed u here