## bahrom7893 4 years ago Zarkon, more series help needed :/

1. Hero

bahrom, you keep asking for serious help :P

2. bahrom7893

Sorry to bother u guys, but i've been working on series non stop for the whole day today, and i can't really solve theoretical stuff right now - only computational. How would I do this question?

3. bahrom7893

4. bahrom7893

@Zarkon another one!

5. Zarkon

$a_n=\frac{1}{n}$ $\sum_{n=1}^{\infty}\left[\frac{1}{n+1}-\frac{1}{n}\right]$ $s_n=\frac{1}{2}-\frac{1}{1}+\frac{1}{3}-\frac{1}{2}+\cdots...\frac{1}{n+1}-\frac{1}{n}$ $s_n=-1+\frac{1}{n+1}$ $s_n\to -1\text{ as }n\to\infty$ but $\sum_{n=1}^{\infty}\frac{1}{n}=\infty$

6. bahrom7893

ty guys!

7. Hero

bahrom, what course are you taking?

8. bahrom7893

this is not mine, im helping a friend. This is calc 2.. I forgot so much stuff lol, and that was only 2 yrs ago.

9. anonymous

hahahaha

10. bahrom7893

one more series incoming zarkon

11. Hero

Pippa, is something funny?

12. anonymous

Yes lol

13. Hero

Would you mind sharing the joke with the rest of us? I didn't get it.

14. anonymous

haha most things that i think r funny nobody else does

15. Hero

You didn't answer my question.

16. anonymous

umm meaning i dont want to share it

17. Hero

Well, you should have laughed to yourself then. Why share the laugh and not the joke?

18. bahrom7893

LOL

19. anonymous

hmmm sorry abt that

20. anonymous

haha bahrom laughed at that

21. ParthKohli

@samjordon what a coincidence that we are viewing this at the same time

22. ParthKohli

3 people on such an old question? o.O

23. anonymous

who is 3?

24. ParthKohli

Ishaan was....he left

25. anonymous

ohhhh lol this was one of my old questions so i recognized it

26. ParthKohli

Lol why are you on this question btw?

27. anonymous

hahahah cuz i saw u on these zarkon last question and all these series questions. Like it appeared next to ur name and i recognized them as mine so i followed u here