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anonymous
 4 years ago
Proof that a^2>0=>a>0.
anonymous
 4 years ago
Proof that a^2>0=>a>0.

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.5How can you prove something that isn't true?

ChrisS
 4 years ago
Best ResponseYou've already chosen the best response.0right... any number squared is greater than 0. example let a=2 2^2=4 so a<0 and a^2>0

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1for any real number a^2>0 but \[\sqrt{a ^{2}}\] can be a or a

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1for complex number \[i ^{2}=1\] where \[i=\sqrt{1}\]

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1anyway that's not true
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