viniterranova
Proof that a^2>0=>a>0.



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Mertsj
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How can you prove something that isn't true?

ChrisS
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right... any number squared is greater than 0.
example
let a=2
2^2=4
so a<0 and a^2>0

Callisto
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for any real number a^2>0 but \[\sqrt{a ^{2}}\] can be a or a

Callisto
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for complex number \[i ^{2}=1\] where \[i=\sqrt{1}\]

Callisto
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anyway that's not true

Mertsj
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Is this horse dead yet?

viniterranova
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Thanks for all.

Mertsj
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yw