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viniterranova

  • 3 years ago

Proof that a^2>0=>a>0.

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  1. Mertsj
    • 3 years ago
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    How can you prove something that isn't true?

  2. ChrisS
    • 3 years ago
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    right... any number squared is greater than 0. example let a=-2 -2^2=4 so a<0 and a^2>0

  3. Callisto
    • 3 years ago
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    for any real number a^2>0 but \[\sqrt{a ^{2}}\] can be a or -a

  4. Callisto
    • 3 years ago
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    for complex number \[i ^{2}=-1\] where \[i=\sqrt{-1}\]

  5. Callisto
    • 3 years ago
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    anyway that's not true

  6. Mertsj
    • 3 years ago
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    Is this horse dead yet?

  7. viniterranova
    • 3 years ago
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    Thanks for all.

  8. Mertsj
    • 3 years ago
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    yw

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spraguer (Moderator)
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